更新集，匹配单个列，在单个查询中匹配多个ID的多个值

Question

我该怎么做：

UPDATE `TEST_TABLE` SET `C1` = 'VALUE_FOR_ID1' WHERE `ID` = 1;
UPDATE `TEST_TABLE` SET `C1` = 'VALUE_FOR_ID2' WHERE `ID` = 2;
UPDATE `TEST_TABLE` SET `C1` = 'VALUE_FOR_ID3' WHERE `ID` = 3;

通过单个查询进行匹配（类似这样）：

UPDATE `TEST_TABLE` SET `C1` = ('VALUE_FOR_ID1','VALUE_FOR_ID2','VALUE_FOR_ID3') WHERE `ID` IN (1,2,3);

Answer 1

您应该可以使用 CASE ：

UPDATE  TEST_TABLE SET C1 =  
CASE
  WHEN ID = 1 THEN 'VALUE_FOR_ID1'
  WHEN ID = 2 THEN 'VALUE_FOR_ID2'
  WHEN ID = 3 THEN 'VALUE_FOR_ID3'
END
WHERE ID IN (1,2,3)