Question

timeout=Xs

我知道我的for循环是错误的，但是我不知道如何使它正确。希望有人可以帮助我。预先感谢

Algorithm fibIterative(integer num)
{
 set i to 1
 set j to 0
 for (k = 1 to num) {
 set j = i + j
 set i = j - i
  }
 return j
}

Answer 1

如果您在Java的循环中声明变量，则在迭代结束时变量将消失。

public int fibIterative(int num) {
    int i = 1;
    int j = 0;

    for (int k = num; k <= num; k++) {
        j = i + j;
        i = j - 1;
    }

    return j;
}

Answer 2

public class fibIterative {

  public int AfibIterative (int num)
  {
    int i = 1;
    int j = 0;

    for (int k = 1; k < num; k++)
    {
         j = i + j;
         i = j - 1;
    }
    return j;   
  }

}

Answer 3

转换后的代码为：

public int fibInteractive(int num) {
    int i = 1;
    int j = 0;

    for (int k = 1; k <= num; k++) {
        j = i + j;
        i = j - 1;
    }
    return j;
}

但是，我认为这段代码不会按照您想要的方式工作。传递4作为参数仍然会产生1作为返回值，因为在每次迭代中重置i的方式是

// Iteration #1
j = 1 + 0
i = 1 - 1
// j's value at this point is 1. i's value is 0.

// Iteration #2
j = 0 + 1
i = 1 - 1
// j's value at this point is 1. i's value is 0.

Answer 4

您的完整Java程序应如下所示：

public class algorithm {

    public static void main(String []args) {
        int ans = fibIterative(23);
        System.out.println(ans);
    }

    static int fibIterative(int num) {
        int i = 1,j = 0,k;
        for(k = 1;k <= num; k++) {
            j = i + j;
            i = j - i;
        }
        return j;
    }
}

我需要将算法转换为Java的帮助

4 个答案: