我正在尝试使用因子水平的“密码本”(格式化为命名列表的列表)将大量数字变量转换为因子变量。我可以使用mutate()
和recode_factor()
一件一件地做,但是我想使用mutate_at()
一件一件地做。我该怎么办?
codebook <- list(
vs = list(`0` = 'V-shaped',
`1` = 'straight'),
am = list(`0` = 'automatic',
`1` = 'manual')
)
mtcars %>%
mutate(vs = recode_factor(vs, levels = !!!(pluck(codebook, 'vs'))))
mtcars %>%
mutate_at(vars(names(codebook)),
funs(recode_factor(., levels = !!!(pluck(codebook, 'somehow_pass_column_name_here?')))))
答案 0 :(得分:1)
一种选择是遍历“密码本”的<div class="items-container">
names
或使用library(tidyverse)
names(codebook) %>%
map(~ mtcars %>%
transmute(!! .x := recode_factor(!! rlang::sym(.x),
levels = !!!(pluck(codebook, .x))))) %>%
bind_cols(mtcars %>%
select(-one_of(names(codebook))), .)
循环
for
答案 1 :(得分:0)
您仍然可以对多个变量使用mutate
,除非您的含义是一对一。我对mutate_at
不太了解,所以也许有人知道该方法。
mtcars %>%
mutate(vs = recode_factor(vs, levels = !!!(pluck(codebook, 'vs'))),
am = recode_factor(am, levels = !!!(pluck(codebook, 'am'))))
mpg cyl disp hp drat wt qsec vs am gear carb
1 21.0 6 160.0 110 3.90 2.620 16.46 V-shaped manual 4 4
2 21.0 6 160.0 110 3.90 2.875 17.02 V-shaped manual 4 4
3 22.8 4 108.0 93 3.85 2.320 18.61 straight manual 4 1
4 21.4 6 258.0 110 3.08 3.215 19.44 straight automatic 3 1
5 18.7 8 360.0 175 3.15 3.440 17.02 V-shaped automatic 3 2
6 18.1 6 225.0 105 2.76 3.460 20.22 straight automatic 3 1
7 14.3 8 360.0 245 3.21 3.570 15.84 V-shaped automatic 3 4
8 24.4 4 146.7 62 3.69 3.190 20.00 straight automatic 4 2
9 22.8 4 140.8 95 3.92 3.150 22.90 straight automatic 4 2
10 19.2 6 167.6 123 3.92 3.440 18.30 straight automatic 4 4