我有主要的桌子商人和第二个桌子终端:
商人桌:
@Entity
@Table
public class Merchants {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id", updatable = false, nullable = false)
private int id;
@Column
private String name;
@Column
private String login;
}
端子台:
@Entity
@Table
public class Terminals {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id", updatable = false, nullable = false)
private int id;
@Column
private int merchant_id;
@Column
private String mode;
}
我要在表格Terminals中设置merchant_id。我想多对多是正确的关系。如何创建它?
答案 0 :(得分:1)
如果您有一个联接表:
关于商人类:
@ManyToMany
@JoinTable(name="MER_TER", joinColumns=@JoinColumn(name="MERCH_ID", referencedColumnName="id"),
inverseJoinColumns=@JoinColumn(name="TERM_ID", referencedColumnName="id"))
private List<Terminals> terminalsList;
在终端类上:
@ManyToMany(mappedBy="terminalsList")
private List<Merchants> merchantsList;
参考页:link
如果没有联接表,请尝试在此处查看:https://stackoverflow.com/a/25018992