Question

嘿所以我有一个问题。我有两张桌子。 table1和table2。表1：

id | car_numbers |  type  |      model   | type_id
1        3           bmw       <model1>       1
2        5           bmw       <model2>       1
3        2         mercedes    <model1>       2
4        4         mercedes    <model2>       2
5        1         chevrolet   <model1>       3

表2：

id | price | type_id
1     100       1
2     200       1
3     300       2 
4     400       2 
5     500       3

我想要的是显示＆＃39;类型＆＃39;＆＃39; car_numbers＆＃39;以及每种车型的平均价格。基本上我在这两个表之间想要的结果是：

  type    | car_numbers | average_price
  bmw            8             150
mercedes         6             350
chevrolet        1             500

我该怎么做？我知道我必须与两个表中常见的type_id相关但我该怎么做？

Answer 1

SELECT type, car_numbers, AVG(price) AS average_price
FROM (SELECT type_id, type, SUM(car_numbers) AS car_numbers
      FROM table1
      GROUP BY type_id) AS t1
JOIN table2 AS t2 ON t1.type_id = t2.type_id
GROUP BY type

DEMO

Answer 2

我想你可能正在寻找

SELECT t.name, sum(Distinct o.car_number) car ,         avg(w.price) price FROM
TYPE t
INNER JOIN tone AS o ON o.type_id = t.id
INNER JOIN ttwo AS w ON w.type_id = t.id
GROUP BY t.name

http://sqlfiddle.com/#!2/1937a/51

Answer 3

这就是你要找的，使用Group By和Avg：

 SELECT type, car_numbers, avg(price) AS average_price
    FROM table1 T1
    INNER JOIN table2 T2
    ON T1.type_id = T2.type_id
    GROUP BY type, car_numbers

表之间的MySQL关系

3 个答案: