Question

每个输出打印一次：

 f1=['part3_pl', 
     'part2_pl', 
     'part3_pl_to_p', 
     'part2_pl_to_p', 
     'part3_pl_to_p_lack', 
     'part2_pl_to_p_lack']


for i in f1:
    for j in f1:
        if i.endswith('pl') and j.endswith('pl_to_p'):
            print(i,j,i+'_output')

返回：

part3_pl part3_pl_to_p part3_pl_output
part3_pl part2_pl_to_p part3_pl_output
part2_pl part3_pl_to_p part2_pl_output
part2_pl part2_pl_to_p part2_pl_output

我想每行打印一次。

正确的输出：

part3_pl part3_pl_to_p part3_pl_output
part2_pl part2_pl_to_p part2_pl_output

Answer 1

请再次检查输出。根据您的代码，输出应为：

for i in f1:
 for j in f1:
    if i.endswith('pl') and j.endswith('pl_to_p'):
        print(i,j,i+'_output')

输出：

part3_pl part3_pl_to_p part3_pl_output
part3_pl part2_pl_to_p part3_pl_output
part2_pl part3_pl_to_p part2_pl_output
part2_pl part2_pl_to_p part2_pl_output

您想要的输出可以通过以下代码实现：

for i in f1:
 for j in f1:
  if i.endswith('pl') and j==i+ '_to_p':
    print(i,j,i+'_output')

获取i和j条件匹配的行

1 个答案: