Question

我在oracle中有这样的查询，但是我想要一个对应的蜂巢SQL。可以有人指导我下面的蜂巢等效物吗

'['|| LISTAGG（t3.measure_title，';'）WITHIN GROUP（ORDER BY t3.measure_title）|| ']'all_measure_desc。如何在Hive中重写。

我在Oracle中的查询是

SELECT 
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk,
    '[' || LISTAGG(t3.measure_title, ';') WITHIN GROUP (ORDER BY t3.measure_title) || ']' all_measure_desc
FROM qms_gic_lifecycle t1 
INNER JOIN dim_member t2 
on t1.member_id = t2.member_id
INNER JOIN dim_quality_measure t3 
on t1.quality_measure_id = t3.quality_measure_id
GROUP BY  
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk;

Answer 1

您可以使用collect_list或collect_set，具体取决于应如何处理重复值。 collect_list保留重复的值，而collect_set保留重复的值。

输出将是值的数组。

SELECT 
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk,
    COLLECT_LIST(t3.measure_title) as all_measure_desc
FROM qms_gic_lifecycle t1 
INNER JOIN dim_member t2 
on t1.member_id = t2.member_id
INNER JOIN dim_quality_measure t3 
on t1.quality_measure_id = t3.quality_measure_id
GROUP BY  
    t1.member_id,
    t2.first_name,
    t2.date_of_birth_sk;

Answer 2

您可以使用collect_list或collect_set，具体取决于应如何处理重复值。 collect_list保留重复的值，而collect_set消除重复的值。

输出将是一个值数组。

您可以使用concat_ws（string SEP，array）函数将结果数组转换为字符串

concat_ws(',', COLLECT_LIST(t3.measure_title) ) as all_measure_desc

相当于LISTAGG的配置单元

2 个答案: