Question

我正在尝试对两个数组进行补充，并用剩余的数据填充第三个数组。我有一个this.subjects对象和一个this.teacerData属性，从中我取出了主题代码并将它们放在两个不同的数组中。现在，我试图过滤掉两个数组中不相等的数据，并将其放入第三个数组中。

subj: Subjects[];
teacherSubjects: string[];
data: string[];
filteredData: string[];
addsubject: AddTeacherSubject = new AddTeacherSubject();
teacherData: TeacherUpdateDataDto = new TeacherUpdateDataDto();

ngOnInit() {
this._curriculumService.getSubject(this.appSession.tenant.tenancyName)
.finally(() => { this.saving = false;})
.subscribe((result: listResultDtoOfSubjectDto) => {
  this.subjects = result.items;
  this.teacherSubjects = this.subjects.map(a => a.code);
  console.log("All Subjects =" + this.teacherSubjects);
 })

this._teacherService.GetTeacherUpdateData(this.appSession.tenant.tenancyName, 
this._sharedService.getMessage())
.finally(()=> { this.saving = false;})
.subscribe((result: TeacherUpdateDataDto) => {
  this.teacherData = result;
  this.subj = this.teacherData.subject;
  this.data = this.subj.map(a => a.code);
})
}

this.subjects DTO

(3) [subjectlistDto, subjectlistDto, subjectlistDto]
0 :
 subjectlistDto {name: "Mathematics", code: "mathematics", classCode: "bscs", 
 classNAME: "BSCS"}
1 :
 subjectlistDto {name: "English", code: "english", classCode: "bscs", 
 classNAME: "BSCS"}
2 :
 subjectlistDto {name: "Islamiat", code: "islamiat", classCode: "bscs", 
 classNAME: "BSCS"}

this.teacherData Dto

subject:Array(2)
0:
{code: "mathematics"}
1:
{code: "english"}

我需要filteredSubjects数组中的已过滤数据。我该怎么办？

Answer 1

这取决于您使用的rxjs版本，但请查看forkJoin或combineLatest。这些使您可以将多个可观察值的结果合并为一个请求。 Combine latest example和Fork join。发射完两组数据后，比较要过滤的项目就很简单了。

编辑：如果只想过滤一次出现的项目的数组，则执行以下操作：

function getDistinctValues(array1, array2): [] {
    const finalArray = [...array1, ...array2];

    finalArray = finalArray.sort((item1, item2) => {
         return item1 === item2 ? 0 : item1 > item2 ? 1 : -1;
    });

    let pointer = finalArray.length-1;

    while(pointer > 0) {
        if(finalArray[pointer] === finalArray[pointer-1]) {
            finalArray.splice(pointer-1, 2);
            pointer--;
        }
        pointer--;
    }
    return finalArray;
}

Answer 2

这是我的做法

只是从ngOnInit和

调用了数据功能

Data(subjec: string[], compar: string[]) {
this.filteredData = [];
for(var i = 0; i< subjec.length; i++) {
  if(compar.indexOf(subjec[i]) === -1){
    this.filteredData.push(subjec[i]);
  }
}
for(var j = 0; j<compar.length; j++) {
  if(subjec.indexOf(compar[j]) === -1){
    this.filteredData.push(compar[j]);
  }
}
return this.filteredData;

}

从第三个数组中的两个数组中筛选数据

2 个答案: