Question

我正在使用json：

 [ { status: 'complete',
    type: 'bid',
    amount: 0,
    units: 0,
    activeId: 146,
    id: 3 },
  { status: 'complete',
    type: 'ask',
    amount: 0,
    units: 0,
    activeId: 146,
    id: 1 },
  { status: 'pending',
    type: 'ask',
    amount: '1009',
    units: 0.996,
    activeId: 146,
    id: 2,
    env: 'newInsert' },
  { status: 'complete',
    type: 'ask',
    amount: 0,
    units: 0,
    id: 2,
    activeId: 146 },
  { status: 'complete',
    type: 'bid',
    amount: 0,
    units: 0,
    activeId: 146,
    id: 4 },
  { status: 'pending',
    type: 'bid',
    amount: 1012,
    units: 3.004,
    id: 11,
    activeId: 146,
    env: 'newInsert' } ]

在这个数组中，我需要删除id相同的对象，并从状态＆＃34; pending＆＃34;到＆＃34;完成＆＃34; 例如：

{ status: 'pending',
    type: 'ask',
    amount: '1009',
    units: 0.996,
    activeId: 146,
    id: 2,
    env: 'newInsert' },
  { status: 'complete',
    type: 'ask',
    amount: 0,
    units: 0,
    id: 2,
    activeId: 146 } 
here same id of type ask and status changed pending to complete.

我试图以一般的方式循环使用foreach并匹配并提取结果但是有任何特定的方法或任何过滤器将事物分组并提取。

Answer 1

使用函数func setTextViewSizeWithContent() { let newSize = self.calculateSize(chatTextView: self.messageTF, chatText: self.messageTF.text, withFixedSize: kMessageViewWidths) self.messageTF.frame = CGRect(x: yourXPosition, y: newYposition, width: yourTextViewWidth, height: newsize.height) self.view.layoutIfNeeded() }和filter

some

var array = [{    status: 'complete',    type: 'bid',    amount: 0,    units: 0,    activeId: 146,    id: 3  },  {    status: 'complete',    type: 'ask',    amount: 0,    units: 0,    activeId: 146,    id: 1  },  {    status: 'pending',    type: 'ask',    amount: '1009',    units: 0.996,    activeId: 146,    id: 2,    env: 'newInsert'  },  {    status: 'complete',    type: 'ask',    amount: 0,    units: 0,    id: 2,    activeId: 146  },  {    status: 'complete',    type: 'bid',    amount: 0,    units: 0,    activeId: 146,    id: 4  },  {    status: 'pending',    type: 'bid',    amount: 1012,    units: 3.004,    id: 11,    activeId: 146,    env: 'newInsert'  }];

var result = array.filter(o => {
  var transition = o.status === 'pending' ? 'complete' : 'pending';  
  return !(array.some((io) => io.id == o.id && io.status === transition));
});

console.log(result);

Answer 2

要删除具有相同ID的项目，可以按id创建对象，然后检查长度（使用reduce）：

var arr = [{    status: 'complete',    type: 'bid',    amount: 0,    units: 0,    activeId: 146,    id: 3  },  {    status: 'complete',    type: 'ask',    amount: 0,    units: 0,    activeId: 146,    id: 1  },  {    status: 'pending',    type: 'ask',    amount: '1009',    units: 0.996,    activeId: 146,    id: 2,    env: 'newInsert'  },  {    status: 'complete',    type: 'ask',    amount: 0,    units: 0,    id: 2,    activeId: 146  },  {    status: 'complete',    type: 'bid',    amount: 0,    units: 0,    activeId: 146,    id: 4  },  {    status: 'pending',    type: 'bid',    amount: 1012,    units: 3.004,    id: 11,    activeId: 146,    env: 'newInsert'  }];


var map = arr.reduce((ac, x) => ({
  ...ac,
  [x.id]: [...(ac[x.id] || []), x]
}), {})


var res = Object.keys(map).reduce((ac, x) =>
  map[x].length > 1 &&
  map[x].some(z => z.status == 'pending') &&
  map[x].some(z => z.status == 'complete') ?
  ac : [...ac, ...map[x]], [])

console.log(res)

在javascript中过滤数组对象中的数据

2 个答案: