Question

我做了一个页面，使用mysqli和php将清单添加到数据库。当我填写信息并单击“提交”按钮时，没有任何反应。字段变为空白。我检查了数据库，但没有放入任何内容。

有人可以帮我弄清楚错误在哪里吗？

这是我的代码：

 <?php
error_reporting(E_ALL);
ini_set('display_startup_errors', 1);
ini_set('display_errors', 1);

include_once("../storescripts/connect_to_mysql.php");
$con = mysqli_connect("$db_host","$db_username","$db_pass","$db_name");

if(isset($_POST['button'])) {

$item_number = mysqli_real_escape_string($con, $_POST['item_number']);
$price = mysqli_real_escape_string($con, $_POST['price']);
$category = mysqli_real_escape_string($con, $_POST['category']);
$desc = mysqli_real_escape_string($con, $_POST['description']);
$qty = mysqli_real_escape_string($con, $_POST['qty']);

// See if that product name is an identical match to another product in the system
    $sql = ("SELECT id FROM products WHERE item_number='$item_number' LIMIT 1");
    $result = mysqli_query($con, $sql);
    $productMatch = mysqli_num_rows($result); // count the output amount
    if ($productMatch > 0) {
        echo 'Sorry you tried to place a duplicate "item_number" into the system, <a href="inventory_list.php">click here</a>';
        exit();
    }
    //Add to inventory now

$sql = "INSERT INTO products ('item_number', 'price', 'category', 'description', 'qty', 'date_added')
    VALUES (?,?,?,?,?,?)";
$stmt = mysqli_stmt_init($con);
if(!mysqli_stmt_prepare($stmt, $sql)) {
    echo "sql error";
} else {
    mysqli_stmt_bind_param($stmt, "ssssss", $item_number, $desc, $price, $catagory, $qty, now());

    mysqli_stmt_execute($stmt);
    echo mysqli_stmt_error($stmt);
    $pid = mysqli_insert_id();
    // Place image in the folder 
    $newname = "$pid.png";
    move_uploaded_file( $_FILES['fileField']['tmp_name'], "../pictures/inventory/$newname");
}
}
?>
<?php
$product_list = '';
include_once("../storescripts/connect_to_mysql.php");
    $con = mysqli_connect("$db_host","$db_username","$db_pass","$db_name");
$sql = "SELECT * FROM products ORDER BY date_added DESC";
$result = mysqli_query($con, $sql);
$product_count = mysqli_num_rows( $result);
if ($product_count > 0) {
    while($row = mysqli_fetch_array($sql)){ 
             $id = $row["id"];
             $item_number = $row["item_number"];
             $price = $row["price"];
             $date_added = strftime("%b %d, %Y", strtotime($row["date_added"]));
             $product_list .= "Product ID: $id - <strong>$product_name</strong> - $$price - <em>Added $date_added</em> &nbsp; &nbsp; &nbsp; <a href='inventory_edit.php?pid=$id'>edit</a> &bull; <a href='inventory_list.php?deleteid=$id'>delete</a><br />";
             $qty = $row["qty"];
    } 
} else {
        $product_list = "You Have No Items In Inventory";
    }
?>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="author" content="samuel jaycox">
<title>Inventory List</title>
<link rel="stylesheet" href="../style.css" type="text/css" media="screen" />
<link rel="shortcut icon" type="image/png" href="pictures/pinky.png">
</head>
<body>
<div align="center" id="mainWrapper">
  <div id="pageContent"><br />
    <div align="right" style="margin-right:32px;"><a href="inventory_list.php#inventoryForm">+ Add New Inventory Item </a></div>
<div align="left" style="margin-left:24px;">
      <h2>Inventory list</h2>
      <?php echo $product_list; ?>
    </div>
    <hr />
    <a name="inventoryForm" id="inventoryForm"></a>
    <h3>
    &darr; Add New Inventory Item Form &darr;
    </h3>
    <form action="inventory_list.php" enctype="multipart/form-data" name="myForm" id="myForm" method="POST">
    <table width="90%" border="0" cellspacing="0" cellpadding="6">
      <tr>
        <td width="20%" align="right">Item Number</td>
        <td width="80%"><label>
          <input name="item_number" type="text" id="item_number" size="64" />
        </label></td>
      </tr>
      <tr>
        <td align="right">Product Price</td>
        <td><label>
          $
          <input name="price" type="text" id="price" size="12" />
        </label></td>
      </tr>
      <tr>
        <td align="right">Category</td>
        <td><label>
          <select name="category" id="category">
          <option value="Bracelets">Bracelet</option>
          <option value="Necklace">Necklace</option>
          <option value="Earring">Earring</option>
          <option value="Childrens">Childrens</option>
          <option value="Sets">Sets</option>
          <option value="Rosary">Rosary</option>
          <option value="Accessories">Accessories</option>
          </select>
        </label>
      </tr>
      <tr>
        <td align="right">Description</td>
        <td><label>
          <textarea name="description" id="description" cols="64" rows="20"></textarea>
        </label></td>
      </tr>
         <tr>
        <td width="20%" align="right">Qty</td>
        <td width="80%"><label>
          <input name="qty" type="text" id="qty" size="9" />
        </label></td>
      </tr>
      <tr>
        <td align="right">Product Image</td>
        <td><label>
          <input type="file" name="fileField" id="fileField" />
        </label></td>
      </tr>      
      <tr>
        <td>&nbsp;</td>
        <td><label>
          <input type="submit" name="button" id="button" value="Submit"/>
        </label></td>
      </tr>
    </table>
    </form>
    <br />
  <br />
  </div>
</div>
</body>
</html>

我是mysqli的新手，只是不知道从哪里开始寻找。任何帮助，将不胜感激。谢谢

Answer 1

将以下代码放在php代码的顶部：

error_reporting(E_ALL);
ini_set('display_startup_errors', 1); // add this too
ini_set('display_errors', 1);

它将显示所有对您有帮助的错误，也请在mysql_stmt_execute()之后添加此代码：

echo mysqli_stmt_error($stmt);

此代码将返回可能会帮助您的mysql错误消息。不要忘记将错误消息粘贴到您的问题。

编辑：关于您的代码，
如果我是正确的，那么您正在尝试使用准备好的语句。应该是

//add ? marker, see official php page about prepared statements
$sql = "INSERT INTO products ('item_number', 'description', 'price', 
'catagory', 'qty', 'date_added')
    VALUES (?, ?, ?, ?, ?, ?)";
$stmt = mysqli_stmt_init($con);
if(!mysqli_stmt_prepare($stmt, $sql)) {
    echo "sql error";
} else {
    //parameters (variable) are binded here. s for string, see official php page for more information. 
    mysqli_stmt_bind_param($stmt, "ssssss", $item_number, $desc, $price, $catagory, $qty, now());

    mysqli_stmt_execute($stmt);
    $pid = mysqli_insert_id();
    // Place image in the folder 
    $newname = "$pid.png";
    move_uploaded_file( $_FILES['fileField']['tmp_name'], 
"../pictures/inventory/$newname");
}
    header("location: inventory_list.php?item addes successfully");
}

请参阅mysqli bind param

编辑2：尝试在$con = mysqli_connect("$db_host","$db_username","$db_pass","$db_name");之后添加此代码以检查您的连接。

if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

还要从$sql = "INSERT INTO products ('item_number', 'price', 'category', 'description', 'qty', 'date_added') VALUES (?,?,?,?,?,?)";中删除'（撇号）

编辑3： php中没有now()函数，您可以将其更改为date("Y-m-d H:i:s")或将准备好的语句代码更改为以下代码。

//now() function is mysql function, so it should be called in sql query.
$sql = "INSERT INTO products ('item_number', 'description', 'price', 
'catagory', 'qty', 'date_added')
    VALUES (?, ?, ?, ?, ?, NOW())";
$stmt = mysqli_stmt_init($con);
if(!mysqli_stmt_prepare($stmt, $sql)) {
    echo "sql error";
} else {
    //remove now() function.
    mysqli_stmt_bind_param($stmt, "sssss", $item_number, $desc, $price, $catagory, $qty);

    mysqli_stmt_execute($stmt);
    $pid = mysqli_insert_id();
    // Place image in the folder 
    $newname = "$pid.png";
    move_uploaded_file( $_FILES['fileField']['tmp_name'], 
"../pictures/inventory/$newname");
}

Answer 2

您的查询值部分是错误的。应该是Values（“ value1”，依此类推）在您的情况下，仅仅是值（value1，那不是正确的方法。

您始终可以回显Sql语句，并在Sql客户端（例如HeidiSQL或MySQL的CLI）中运行查询。

我正在尝试使用mysqli和php将产品添加到数据库，但未添加任何内容

2 个答案: