Question

我正在尝试通过AJAX提交表单以将我的数据插入数据库，当我按下提交按钮时数据没有插入..

            $invoice_number = rand(0, 99999);
        $TransactionInsert = array(
            'date'           => $this->input->post('funds_arrival_date'),
            'description'    => 'Payment against invoice #' . '<a href="/reservations/database/edit/' . $this->input->post('reservations') . '">' . $this->input->post('reservations') . '</a>' . ' via ' . '"' . $this->input->post('paid_to') . '"' . ' method',
            'product'        => $this->input->post('reservations'),
            'credit'         => $this->input->post('actual_amount'),
            'credit_cur'     => $this->input->post('currency_name'),
            'credit_cur_val' => (int)$this->input->post('currency_value'),
            'debit'          => 0,
            'parent_invoice' => $invoice_number
        );
        $this->db->insert('transactions', $TransactionInsert);

jQuery

//Finish the process, POST AJAX...
    $('button[name=submit-transaction]').live("click", function (e) {
        var a = getTransactionValues();
        e.preventDefault();
        $.ajax({
            url: '/transactions/submit',
            type: 'POST',
            data: {
                reservations:       a.reservations,
                amount:             a.amount,
                currency_value:     a.currency_value,
                currency_name:      a.currency_name,
                actual_amount:      a.actual_amount,
                actual_remaining:   a.actual_remaining,
                funds_arrival_date: a.funds_arrival_date,
                paid_to:            a.paid_to,
                checkbox:           a.checkbox
            },
            success: function (data) {
                location.reload();
            },
        });
    });
}

    /*
*   Gathering values and getting them
*/
function getTransactionValues() {
    var o = {};
    o.parent_id           = $('.dbase_id').val();
    o.reservations        = [];
    $('#custom-headers option:selected').each(function (i, selected) {
        o.reservations[i] = $(selected).val();
    });
    o.amount              = $('input[name=amount-price]').val();
    o.currency_value      = $('input[name=currency-value]').val();
    o.currency_name       = $('.currency_appendto option:selected').html();
    o.actual_amount       = $('input[name=actual-amount]').val();
    o.actual_remaining    = $('input[name=actual-remaining]').val();
    o.funds_arrival_date  = $('input[name=funds-arrival]').val();
    o.paid_to             = $('.paidto option:selected').html();
    o.checkbox            = $('.multi-transaction:checked').map(function () {
        return this.value
    }).get();
    return o;
}

我不知道页面没有向我显示什么错误，并且数据未提交给数据库

Answer 1

我可能错了，但似乎你的o.reservations = [];部分正在返回一些东西，在你的PHP代码中你没有循环它并尝试插入一个你需要循环的批量$this->input->post('reservations');这个或访问第一个/第二个密钥..无论你需要插入什么$this->input->post('reservations')[0];尝试：

        $TransactionInsert = array(
        'date'           => $this->input->post('funds_arrival_date'),
        'description'    => 'Payment against invoice #' . '<a href="/reservations/database/edit/' . $this->input->post('reservations')[0] . '">' . $this->input->post('reservations')[0] . '</a>' . ' via ' . '"' . $this->input->post('paid_to') . '"' . ' method',
        'product'        => $this->input->post('reservations')[0],
        'credit'         => $this->input->post('actual_amount'),
        'credit_cur'     => $this->input->post('currency_name'),
        'credit_cur_val' => (int)$this->input->post('currency_value'),
        'debit'          => 0,
        'parent_invoice' => $invoice_number
    );

Answer 2

我也看到url中的ajax调用中的基本url不正确，我将分享我通常使用的ajax调用

我假设您使用提交方法

调用事务控制器

    $("#your_html_item_id").bind("click",function()
    {
        var target_url = '<?php echo(base_url()."transactions/submit") ; ?>';
        $.ajax
        (
        {
            url : target_url,
            type: "POST",
            cache: false,
            data: 
            {
                key1:       value1,
                key2:       value2,
                key3:       value3
            },
            success: function(data)
            {
                alert(1);
            },
            error: function(jqXHR, textStatus, errorThrown)
            {
                alert("error during database query");
            }
        });

    });

如果您看到一个消息框为1，则表示ajax调用成功

Answer 3

您应该检查您的php错误日志和数据库错误日志。

如果您不知道在哪里找到它......您可以谷歌搜索：）

试图插入数据库但没有任何反应

3 个答案: