Question

我需要在MYSQL表中搜索可能不在行中的任何字符串，然后将其打印在屏幕上。我可以使用python轻松地做到这一点，但我仍在学习PHP，它与众不同，并且不熟悉它的完成方式。

该行有多组用逗号分隔的单词，因此我需要对与$ string匹配的任何单词使用LIKE

$string = 'text';
$db = mysqli_connect("localhost", "root", "", "data");
$result = mysqli_query("SELECT row FROM table WHERE row LIKE '%$string%'");
if($string == $result){
    echo "String found";
}else{
    echo "No string found!";
}

Answer 1

找到了here。

您需要像这样遍历query（）返回的结果游标：

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
    }
} else {
    echo "0 results";
}
$conn->close();

PHP搜索字符串是否在MYSQL行中

1 个答案: