Question

基本上我有一张这样的表：

|id|username|password|email|hasAlphaKey|
 1  test1    test2    -----      1
 2  test2    test3    -----      0

我想检测hasAlphaKey == 1我是如何实现这一目标的呢？

我试过这样做：

$hasAlphaKey = mysql_query("SELECT * FROM Accounts WHERE hasAlphaKey='1'");
$check_for_key = mysql_num_rows($hasAlphaKey);

if($check_for_key == 1) {
  echo 'You have an alpha key!';
}

如果使用帐户 test1 导致它在hasAlphaKey中的值为1 但是当我登录test2时，它仍会执行第echo 'You have an alpha key!';行，但该值设置为零？

我可以帮忙吗？：）

Answer 1

|id|username|password|email|hasAlphaKey|
 1  test1    test2    -----      1
 2  test2    test3    -----      0


$qry="SELECT * FROM Accounts WHERE hasAlphaKey=1 AND username='test2'";
$result123 = mysql_query($qry);
$check_for_key = mysql_num_rows($result123);

if($check_for_key == 1) {
  echo 'You have an alpha key!';
}

对于username ='test1'，它应该回显。

对于username ='test2'，它不应回显

Answer 2

test1有alpha键，test2没有。所以在表中有1个带有alpha键的元素。代码按预期工作。也许你想这样做

SELECT * FROM Accounts WHERE hasAlphaKey=1 AND username='test2'

Answer 3

$hasAlphaKey = mysql_query("SELECT * FROM Accounts");
$check_for_key = mysql_num_rows($hasAlphaKey);
$row = mysql_fetch_assoc($hasAlphaKey);
$hasKey = $row['hasAlphaKey'];
if($hasKey == 1) {
     echo 'You have an alpha key!';
}

检测行中是否包含值

3 个答案: