因此，自从两天以来，我一直在努力寻找答案，我仍然是一名学生，不知道是否无法理解其他帖子，或者我的案情太具体而无法解决以及我在互联网上找到的任何内容。
正如我在标题中所说的，我有一个称为“ piece”的2D类数组，每当我开始游戏时，它都会创建一个具有随机行和列的2D数组（快速解释一下目标是将所有块连接起来为了赢球，您可以旋转棋子以建立连接）。 OnMouseClick（）一切正常。功能，但是由于我需要使用键盘上的箭头进行归档，因此遇到了一些麻烦。
我有一个函数，每次我启动或重置它时都会生成谜题（因此在Start（）中调用，而在我按下“清除”按钮时在Update（）中调用它）像这样：
public piece[,] pieces;
public GameObject Cursor;
void GeneratePuzzle()
{
pieces = new piece[width, height];
int[] auxValues = { 0, 0, 0, 0 };
for (int h = 0; h < height; h++)
{
for (int w = 0; w < width; w++)
{
//width restrictions
if (w == 0)
auxValues[3] = 0;
else
auxValues[3] = pieces[w - 1, h].values[1];
if (w == width - 1)
auxValues[1] = 0;
else
auxValues[1] = Random.Range(0, 2);
//heigth resctrictions
if (h == 0)
auxValues[2] = 0;
else
auxValues[2] = pieces[w, h - 1].values[0];
if (h == height - 1)
auxValues[0] = 0;
else
auxValues[0] = Random.Range(0, 2);
//tells piece type
int valueSum = auxValues[0] + auxValues[1] + auxValues[2] + auxValues[3];
if (valueSum == 2 && auxValues[0] != auxValues[2])
valueSum = 5;
go = (GameObject)Instantiate(piecesPrefabs[valueSum], new Vector3(origin.position.x + w, origin.position.y, origin.position.z + h), Quaternion.identity);
go.transform.parent = gameObject.transform;
while (go.GetComponent<piece>().values[0] != auxValues[0] ||
go.GetComponent<piece>().values[1] != auxValues[1] ||
go.GetComponent<piece>().values[2] != auxValues[2] ||
go.GetComponent<piece>().values[3] != auxValues[3])
{
go.GetComponent<piece>().RotatePiece();
}
pieces[w, h] = go.GetComponent<piece>();
instantiatedPieces.Add(go.gameObject);
}
}
}
到目前为止，我一直在尝试类似的操作以使光标在此数组中移动：
public void Update()
{
for (int h = 0; h < height; h++)
{
if (Input.GetKeyDown(KeyCode.LeftArrow))
{
h++;
if (h > height)
h = 0;
}
for (int w = 0; w < width; w++)
{
if (Input.GetKeyDown(KeyCode.UpArrow))
{
w++;
if (w > width)
w = 0;
}
// Cursor.transform.position = pieces[w, h].transform.position; ==> I suppose this is where it should be
}
}
}
但是我最终超出了范围，或者光标是如此之快，以至于看不到它遍及每片。为了清楚起见，我希望能够按行和列将光标移至该2D数组中的每个片段上（我想这是要走的路），之后，我需要从我的光标结束的特定棋子的棋子类，但我想我可以找到它。
英语不是我的母语，很抱歉，如果您需要更多信息来帮助我，我会尽力而为。 非常感谢您的任何帮助，我们将不胜感激！
答案 0 :(得分：1)
我不确定您要使用代码做什么。 我没有得到您在更新中使用以下行的内容。
private static TableSchema TableSchema;
public static void main(String[] args) {
try {
TableSchema = TableSchemaReader.read(TableSchemaResource);
} catch (IOException e) {
log.error("Table schema can not be read from {}. Process aborted.", TableSchemaResource);
return;
}
DataflowDfpOptions options = PipelineOptionsFactory.fromArgs(args)
//.withValidation()
.as(DataflowDfpOptions.class);
Pipeline pipeline = Pipeline.create(options);
Stopwatch sw = Stopwatch.createStarted();
log.info("DFP data transfer from GS to BQ has started.");
pipeline.apply("ReadFromStorage", TextIO.read()
.from("gs://my-test/stream/*.gz")
.withCompression(Compression.GZIP))
.apply("TransformToTableRow", ParDo.of(new TableRowConverterFn()))
.apply("WriteToBigQuery", BigQueryIO.writeTableRows()
.to(options.getTableId())
.withMethod(STREAMING_INSERTS)
.withCreateDisposition(CREATE_NEVER)
.withWriteDisposition(WRITE_APPEND)
.withSchema(TableSchema)); //todo: use withJsonScheme(String json) method instead
pipeline.run().waitUntilFinish();
log.info("DFP data transfer from GS to BQ is finished in {} seconds.", sw.elapsed(TimeUnit.SECONDS));
}
/**
* Creates a TableRow from a CSV line
*/
private static class TableRowConverterFn extends DoFn<String, TableRow> {
@ProcessElement
public void processElement(ProcessContext c) throws Exception {
String[] split = c.element().split(",");
//Ignore the header line
//Since this is going to be run in parallel, we can't guarantee that the first line passed to this method will be the header
if (split[0].equals("Time")) {
log.info("Skipped header");
return;
}
TableRow row = new TableRow();
for (int i = 0; i < split.length; i++) {
//This throws NEP!!!
TableFieldSchema col = TableSchema.getFields().get(i);
//String is the most common type, putting it in the first if clause for a little bit optimization.
if (col.getType().equals("STRING")) {
row.set(col.getName(), split[i]);
} else if (col.getType().equals("INTEGER")) {
row.set(col.getName(), Long.valueOf(split[i]));
} else if (col.getType().equals("BOOLEAN")) {
row.set(col.getName(), Boolean.valueOf(split[i]));
} else if (col.getType().equals("FLOAT")) {
row.set(col.getName(), Float.valueOf(split[i]));
} else {
//Simply try to write it as a String if
//todo: Consider other BQ data types.
row.set(col.getName(), split[i]);
}
}
c.output(row);
}
}
尝试删除该行。
答案 1 :(得分：1)
尝试一下：
public void Update()
{
for (int h = 0; h < height; h++)
{
if (Input.GetKeyDown(KeyCode.LeftArrow))
{
h++;
if (h > height)
h = 0;
}
}
for (int w = 0; w < width; w++)
{
if (Input.GetKeyDown(KeyCode.UpArrow))
{
w++;
if (w > width)
w = 0;
}
// Cursor.transform.position = pieces[w, h].transform.position; ==> I suppose this is where it should be
}
}
或者这个：
public void Update()
{
for (int h = 0; h < width; h++)
{
if (Input.GetKeyDown(KeyCode.LeftArrow))
{
h++;
if (h > height)
h = 0;
}
}
for (int w = 0; w < height; w++)
{
if (Input.GetKeyDown(KeyCode.UpArrow))
{
w++;
if (w > width)
w = 0;
}
// Cursor.transform.position = pieces[w, h].transform.position; ==> I suppose this is where it should be
}
}
答案 2 :(得分：1)
对于WindowsForms，我将使用KeyDown事件并增加/减少h或w，并在到达边缘时将它们设置为零或最大值。
答案 3 :(得分：1)
以下是我的评论示例：
如果要在不依赖按键的情况下将光标移动到要更新的数组元素上，则不需要for循环。
// Declared outside of your update makes these class variables that
// will live as long as this object exists.
int w = 0; // May be better to change this to cursorXPos
int h = 0; // May be better to name this cursorYPos
public void Update()
{
if (Input.GetKeyDown(KeyCode.LeftArrow))
{
w--;
if (w < 0)
w = width -1;
}
else if (Input.GetKeyDown(KeyCode.RightArrow))
{
w++;
if (w >= width)
w = 0;
}
if (Input.GetKeyDown(KeyCode.UpArrow))
{
h--;
if (h < 0)
h = height -1;
}
else if (Input.GetKeyDown(KeyCode.DownArrow))
{
h++;
if (h >= height)
h = 0;
}
Cursor.transform.position = pieces[w, h].transform.position;
}