编辑：

Question

我正在尝试合并两个有重叠结果的数组和一些不同的数组，如下所示：

array(
 [0] => array('name' => 'John', 'score' => '9');
 [1] => array('name' => 'Pete', 'score' => '2');
 [2] => array('name' => 'Eric', 'score' => '7');
)

和

array(
 [0] => array('name' => 'Lisa', 'score' => '1');
 [1] => array('name' => 'Pete', 'score' => '5');
 [2] => array('name' => 'Mary', 'score' => '4');
)

这应该导致一个包含五个（不是六个）结果的数组。皮特的得分应该是他两个得分的总和，即'7'。

是否有一个简单的功能，或者我是否必须预先处理一个（或两个？）列表并相互检查它们？我不知道如何开始这个，正确方向的指针将不胜感激！

编辑：

所以..实际上两个数组都填充了对象..任何新的想法？

Answer 1

创建一个临时查找数组并从中重新创建最终数组。这是一个使用额外空间的O（n）算法。请在此处查看：http://codepad.org/4aL5KMR4

<?php

$arr1 =
array(
      array('name' => 'John', 'score' => '9'),
      array('name' => 'Pete', 'score' => '2'),
      array('name' => 'Eric', 'score' => '7'),
      );

$arr2=

array(
      array('name' => 'Lisa', 'score' => '1'),
      array('name' => 'Pete', 'score' => '5'),
      array('name' => 'Mary', 'score' => '4'),
      );

$res = array();
$revLookUp = array();
foreach($arr2 as $row)
{
  if(isset($revLookUp[$row['name']]) == true)
    $revLookUp[$row['name']] += $row['score'];
  else
    $revLookUp[$row['name']] = $row['score'];
}

foreach($arr1 as $row)
{
  if(isset($revLookUp[$row['name']]) == true)
    $revLookUp[$row['name']] += $row['score'];
  else
    $revLookUp[$row['name']] = $row['score'];
}


foreach($revLookUp as $key => $value){
  $res[] = array('name' => $key, 'score' => $value);
}

print_r($res);

?>

Answer 2

这将完成工作

$array1 = array(
      array('name' => 'John', 'score' => 9),
      array('name' => 'Pete', 'score' => 2),
      array('name' => 'Eric', 'score' => 7),
      );

$array2 = array(
      array('name' => 'Lisa', 'score' => 1),
      array('name' => 'Pete', 'score' => 5),
      array('name' => 'Mary', 'score' => 4),
      );

$result = array();
$names = array();

foreach ($array2 as $elem2){
    $cc = 0;
    foreach ($array1 as $key => $elem1){
        $cc++;
        if ($elem1['name'] == $elem2['name']) {
            $names[$elem1['name']] = $elem1['score'] + $elem2['score'];
            break;
        }
        else if ($cc == count($array1)) {
            array_push ($result, $elem2);
        }
    }
}

foreach ($array1 as $elem1){
    if ($names[$elem1['name']]){
        $elem1['score'] = $names[$elem1['name']];
    }
    array_push ($result, $elem1);
}
print_r($result);

Answer 3

由于不同，此任务没有任何功能。使用此算法：

function merge($array1, $array2)
{
  $result = array();
  $count = (count($array1) > count($array2)) ? count($array1) : count($array2);
  for($i=0; $i<$count; $i++)
  {
    if($array1[$i]['name'] != $array2[$i]['name'])
    {
       $result[] = $array1[$i];
       $result[] = $array2[$i];
    }
    else
    {
       $array1['score'] += $array2['score'];
       $result[] = $array1[$i];
    }
  }
  return $result;
}

抱歉我的英语不好。祝你好运！

Answer 4

function vector_sum($a, $b) {
  $arrays=func_get_args();
  $res=array(); $result=array();
  foreach($arrays as $current) {
    $res=array_reduce($current, function($res, cur){
      @$res[$cur['name']]+=$cur['score'];
      return $res;
    }, $res);
  }

  // sums done. put the result array in shape
  foreach ($res ad $name=>$score) 
    array_push($result, array('name'=>$name, 'score'=>$score));
  }
  return $result;
}

未经测试，它应该使用任意数组编号

Answer 5

如果您按照以下方式稍微重新设计数组：

希望有所帮助

<?php

$a = array(
 'John' => '9',
 'Pete' => '2',
 'Eric' => '7',
);

$b = array(
 'Lisa' => '1',
 'Pete' => '5',
 'Mary' => '4',
);


$newArray = $a;
foreach($b as $key => $value) {
    if(array_key_exists($key, $newArray)){
     $newArray[$key] += $value;
    }else{
     $newArray[$key] = $value;
    }
}


print_r($newArray);


?>

您也可以在此处查看结果：http://codepad.org/9hKF8oVC

合并两个数组，累加重叠结果

编辑：

5 个答案: