Question

我正在使用datetime来存储每个提供商输入新数据的日期。使用以下查询来提取结果：

SELECT COUNT(id) AS addedCount,
date(date_added) AS dateAdded,
provider_name as provider 
FROM `table` WHERE `table`.`id` IN (SELECT `table`.`id` FROM `table` 
WHERE     `table`.`active` = '1') 

GROUP BY dateAdded
ORDER BY dateAdded DESC

数组如下所示：

array(1343) {
    [0]=>
    array(3) {
        ["addedCount"]=>
        string(1) "2"
        ["dateAdded"]=>
        string(10) "2012-03-03"
        ["provider"]=>
        string(5) "Provider_1"
    }
    [1]=>
    array(3) {
        ["addedCount"]=>
        string(1) "1"
        ["dateAdded"]=>
        string(10) "2012-03-03"
        ["provider"]=>
        string(5) "Provider_1"
   }
  [2]=>
  array(3) {
      ["addedCount"]=>
      string(1) "1"
      ["dateAdded"]=>
      string(10) "2012-03-03"
      ["provider"]=>
      string(5) "Provider_2"
   }
  [3]=>
  array(3) {
      ["addedCount"]=>
      string(1) "1"
      ["dateAdded"]=>
      string(10) "2012-03-03"
      ["provider"]=>
      string(5) "Provider_2"

我需要结果来计算“addedCount”的总数，其中“dateAdded”和“provider”匹配，以便最终的数组看起来像：

addedCount  dateAdded   provider
3           2012-03-03  provider_1
2           2012-03-03  provider_2

我已经尝试不知疲倦地搜索SO并重建数组，但是花了好几个小时后，我最终重建了原始形式的数组，

提前谢谢！

Answer 1

您可以将数据用作索引，以便对类似数据进行分组，例如：

$groupArray = array();
foreach ( $providerArr as $provider )
{
    // Using the grouping info (date & name) as a key to our grouping array

    $key = $provider[ 'dateAdded' ] . $provider[ 'provider' ];
    if ( !isset( $groupArray[ $key ] ) )
    {
        // Our grouping array does not have the specific combination of date & name yet
        // so save the first occurance of data for this combination.

        $groupArray[ $key ] = $provider;
    }
    else
    {
        // The unique combination of date & name already exists so just update the count

        $groupArray[ $key ][ 'addedCount' ] += $provider[ 'addedCount' ];
    }
}

// Now print

foreach ( $groupArray as $data )
{
    echo( "{$data[ 'addedCount' ]} - {$data[ 'dateAdded'} - {$data[ '$provider' ]}<br/>" );
}

重新排列数组以组合重叠结果

1 个答案: