Question

int main()
{
    srand(time(NULL)); //seeding rand with a starting value


    const string ranks[] = { "Ace",   "Two",  "Three", "Four", "Five",  "Six", "Seven",
                             "Eight", "Nine", "Ten",   "Jack", "Queen", "King" };

    const string suits[] = {
        "Diamonds", "Hearts", "Spades", "Clubs"
    }; //array with 52 cards,4 suits each with 13 ranks(1 to King)

    int ranksindex = rand() % 13; //random index for drawing card 1
    int suitsindex = rand() % 4;

    int ranksindex2 = rand() % 13; // random index for drawing card 2
    int suitsindex2 = rand() % 4;

    string card1, card2;
    int    counter = 0;
    int    times   = 1000;
    int    i;

    for (i = 0; i < times; i++)
    {
        card1 = ranks[ranksindex] + " of "
                + suits[suitsindex]; // two random cards with the ranks and suits
        card2 = ranks[ranksindex2] + " of " + suits[suitsindex2];

        if (card1 == card2)
        {
            card2 = ranks[ranksindex] + " of "
                    + suits[suitsindex]; // to make the cards always different
        }

        cout << "The two cards drawn are : " << card1 << " and " << card2 << endl
             << endl; //display card the two cards drawn
    }
}

当我尝试运行程序时，它没有完成程序，卡在了那里，我该怎么办才能解决此问题？

下面是我的输出的图片，它将运行但不会完成整个程序并显示计数器

Answer 1

int ranksindex = rand() % 13; //random index for drawing card 1
int suitsindex = rand() % 4; 

int ranksindex2 = rand() % 13; // random index for drawing card 2
int suitsindex2 = rand() % 4;

上面的代码应该在for循环内。

您想每转查找随机的ranksIndex和suitsIndex。现在，您只找到它一次，并在for循环中多次使用它。

Answer 2

重新格式化代码后可以看到，随机值是在循环外部读取的，因此必须将此代码移入循环内部。

我相信，通过获得2个随机数，所选卡的结果分布将不太均匀。

由于您要查找52张卡中的1张，因此只能生成1个随机值，然后将该值映射到一张卡上。

这里是一个例子：

constexpr auto card_ranks_count = 13;
constexpr auto card_suits_count = 4;

const int random_card = rand() % (card_ranks_count * card_suits_count);

const auto indexes = std::div(random_card, card_ranks_count);

const int ranksindex = indexes.rem;
const int suitsindex = indexes.quot;

循环播放一对卡片100次（卡片组）

2 个答案: