Question

我有两个数组，我想将第一个数组的值添加到第二个数组。我是通过.push实现的。

数组初始化：

<script>
var needsPrecision = ["Decimal"];
var needsLength = ["Binary", "Char", "NChar", "NVarChar", "VarBinary", "VarChar"];
needsLength.push(needsPrecision);

此后，我遍历了它们，并且"Decimal"在needsLength数组中：

for (var i = 0; i < needsLength.length; i++) {
    alert (needsLength[i]);
}
alert("---");
for (var i = 0; i <needsPrecision.length; i++) {
    alert(needsPrecision[i]);
}

但是，如果我在$(document).ready()中对其进行检查，它将返回-1-> false：

$(document).ready(function () {
    alert($.inArray("Decimal", needsLength));
}
</script>

我错过了一些示波器吗？（对不起，我对jquery还是很陌生的）

Answer 1

needsPrecision是一个数组。您需要Array.concat像下面这样的数组。

var needsPrecision = ["Decimal"];
var needsLength = ["Binary", "Char", "NChar", "NVarChar", "VarBinary", "VarChar"];
needsLength = needsLength.concat(needsPrecision);

Answer 2

您还可以使用扩展语法组合两个数组，然后获取索引：

var needsPrecision = ["Decimal"];
var needsLength = ["Binary", "Char", "NChar", "NVarChar", "VarBinary"];
needsLength = [...needsLength, ...needsPrecision];
console.log(needsLength);
alert($.inArray("Decimal", needsLength));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

您甚至可以使用Array.push.apply()组合数组，然后获取索引：

var needsPrecision = ["Decimal"];
var needsLength = ["Binary", "Char", "NChar", "NVarChar", "VarBinary"];
needsLength.push.apply(needsLength, needsPrecision);
console.log(needsLength);
alert($.inArray("Decimal", needsLength));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Array.push在Array中，但是$ .inArray返回“ false”

2 个答案: