Question

我一直在搜索Stacked / Nested if else语句，elif似乎无法满足我的需要。目的是打印所有偶数，平方数和立方数，并突出显示哪些既是平方数又是立方数。这是我的代码：

import math
rn = 0
for n in range(1,100,1):
    if rn is 0:
        if n%2 is 0:
            print(n, " is an even number")           
        else:
            rn = 1         
        if math.sqrt(n) is int:
            print(n, " is a square number")
            if n**(1/3) is int:
                print(n, " is a Cube number too")
                continue
            else:
                print(n, "is only a square number")
                continue

        else:
            rn = 1
    if rn is 1:
        if n**(1/3) is int:
            print(n, " is a Cube only number")
        else:
            rn = 0
            continue

在递增n之前，代码未移至下一个if语句。

输出：

   2  is an even number
   4  is an even number
   6  is an even number

还有另一种继续或中断但停留在同一循环中的方法吗？预先感谢

Answer 1

import math
rn = 0
d=0.
for n in range(1,100,1):
    if rn is 0:
        if n%2 is 0:
            print(n, " is an even number")
        else:
            rn = 1
        if math.sqrt(d).is_integer():
            print(n, " is a square number")
            if float(n**(1-3)).is_integer():
                print(n, " is a Cube number too")
                continue
            else:
                print(n, "is only a square number")
                continue

        else:
            rn = 1
    if rn is 1:
        if n**(1-3) is int:
            print(n, " is a Cube only number")
        else:
            rn = 0
            continue

使用float.is_integer()可以解决以前的问题，即is int返回False进行任何输入。还要注意，这将给出从1到100的所有数字>> {} is a square number，因为您正在做math.sqrt(d)并且d是0，因此平方根始终是整数{{1 }}

如果else语句堆叠并嵌套，则if语句不移至next

1 个答案: