Question

我有一个嵌套的列表视图，如下所示。它在一个按钮中显示学生姓名及其对应的标记。当我点击按钮时，我想获得简洁的行索引。我怎么才能得到它？

INT

  <ListView x:Name="Mainlist" HorizontalAlignment="Stretch">
     <ListView.ItemTemplate>
     <DataTemplate x:DataType="local:ClassRoomList">
       <Grid>
        <Grid.ColumnDefinitions>
         <ColumnDefinition Width="*" ></ColumnDefinition>
         </Grid.ColumnDefinitions>
          <ListView x:Name="sublist1" ItemsSource="{x:Bind CurrentStudentsArray}" Grid.Column="0" BorderBrush="Black" BorderThickness="0,0,0,1" HorizontalAlignment="Stretch" >
              <ListView.ItemTemplate>
                 <DataTemplate x:DataType="local:CurrentStudentsList">
                    <Grid>
                       <Grid.ColumnDefinitions>
                          <ColumnDefinition Width="*"></ColumnDefinition>
                          <ColumnDefinition Width="*"></ColumnDefinition>
                        </Grid.ColumnDefinitions>
                           <TextBlock Foreground="Black" FontWeight="Bold" Grid.Column="0" TextWrapping="Wrap"  HorizontalAlignment="Left" VerticalAlignment="Center" Text="{x:Bind StudentName}"/>
                               <ListView x:Name="sublist2" ItemsSource="{x:Bind StudentsMarksArray}" Grid.Column="1" HorizontalAlignment="Stretch" >
                                  <ListView.ItemTemplate>
                                   <DataTemplate x:DataType="local:StudentsMarksList">
                                      <Button Width="120" Height="40" Text="{x:Bind MarkInEnglish}"  Click="ShowDetails_btn_Click">
                                       </Button>
                                    </DataTemplate>
                                   </ListView.ItemTemplate>
                                </ListView>
                         </Grid>
                    </DataTemplate>
              </ListView.ItemTemplate>
            </ListView>
        </Grid>
     </DataTemplate>
   </ListView.ItemTemplate>

Listview如下所示，

 private void ShowDetails_btn_Click(object sender, RoutedEventArgs e)
{
    int selectedIndx = Mainlist.SelectedIndex; //always return -1
}

我使用的

Class如下所示，它的值绑定到一个可观察的集合。并将此集合设置为listview的itemsource

 DIANA 35
 DHAYA 45
 HAYAN 55

}

  namespace TestClass
 {
 public class ClassRoomList
{
    public int ClassID{ get; set; }
    public ObservableCollection<CurrentStudentsList> CurrentStudentsArray { get; set; }
}

public class CurrentStudentsList
{
    public string StudentName { get; set; }
    public ObservableCollection<StudentsMarksList> StudentsMarksArray { get; set; }

}
public class StudentsMarksList
{
    public string MarkInEnglish { get; set; }
    public string MarkInMaths{ get; set; }
}

Answer 1

您可以使用def upgrade(): # ### commands auto generated by Alembic - please adjust! ### op.create_table('bookmark', sa.Column('date_created', sa.DateTime(), nullable=True), sa.Column('date_modified', sa.DateTime(), nullable=True), sa.Column('bookmark_id', sa.Integer(), nullable=False), sa.Column('user_id', sa.Integer(), nullable=True), sa.Column('name', sa.String(length=255), nullable=True), sa.Column('url', sa.String(length=255), nullable=True), sa.ForeignKeyConstraint(['user_id'], ['users.id'], ), sa.PrimaryKeyConstraint('bookmark_id') )类获得对父ListView和父ListViewItem的引用。然后，您可以使用VisualTreeHelper的{{1}}方法来获取索引：

IndexOf

Answer 2

发送方将包含引发事件的行项目的数据上下文。您可以在Click处理程序中对其进行处理：

private void ShowDetails_btn_Click(object sender, RoutedEventArgs e)
{
     StudentMark selectedItem= ((FrameworkElement)sender).DataContext as StudentMark ;
     //If you are specially interested in index you could get it by:
     int index= CurrentStudentsList.StudentsMarksArray.IndexOf(selectedItem);

}

`

从嵌套的listview按钮中获取RowIndex-UWP

2 个答案: