Question

我给了一个嵌套网格。当点击子网格中的按钮时，我必须得到父网格行索引。我使用过这种类型的代码

protected void GridView2_RowCommand(object sender, GridViewCommandEventArgs e)
{
    if (e.CommandName == "go")

          {

        GridViewRow Gv2Row = (GridViewRow)((LinkButton)e.CommandSource).NamingContainer;
        GridView Childgrid = (GridView)(Gv2Row.Parent.Parent);

        GridViewRow Gv1Row = (GridViewRow)(Childgrid.NamingContainer);
        GridView Parentgrid = (GridView)(Gv1Row.Parent.Parent);
        }
}

但是它不起作用.. 显示类型转换错误。怎么解决..

Answer 1

请尝试使用以下代码段。

protected void GridView2_RowCommand(object sender, GridViewCommandEventArgs e)
{
    if (e.CommandName == "go")
    {
        GridViewRow Gv2Row = (GridViewRow)((LinkButton)sender).NamingContainer;
        GridView Childgrid = (GridView)(Gv2Row.Parent.Parent);
        GridViewRow Gv1Row = (GridViewRow)(Childgrid.NamingContainer);
        int b = Gv1Row.RowIndex;
        // Access your parent grid index here
    }
}

Answer 2

您在下面的评论行中错过了额外的(和)，导致typecasting错误。并且您不需要代码中的最后一个语句，因为您已找到父网格。

我建议您最好更改代码中parent/child gridview/row对象的命名约定，以便让它更好地理解，详见下文。

if (e.CommandName == "go")
{
   // GridViewRow Gv2Row = (GridViewRow)((LinkButton)e.CommandSource).NamingContainer;
   GridViewRow childrow = (GridViewRow)(((LinkButton)e.CommandSource).NamingContainer);
   GridView parentgrid = (GridView)(childrow.Parent.Parent);
   GridViewRow parentrow = (GridViewRow)(parentgrid.NamingContainer);
   int parentrowindex = parentrow.RowIndex;
}

父网格rowindex从子网格按钮单击ASP.net

2 个答案: