这是this问题的延续。请不要将此问题标记为重复问题,因为它存在我需要解决的其他错误。
链接的TL; DR:
所以我当时在问我的加密程序在python中出现Unicode错误,有人告诉我只需在utf-8中对密码进行编码即可。
现在我有第二个问题,它说IV不是16字节,因此我通过在IV后面放置print(len(IV))
并进行了3次测试后,在中间将它只返回16次来进行检查。字符,并且结束字符大于16(例如:37、35、28等)。
如何解决这个问题,使IV始终返回16个字节?
完整错误:
Traceback (most recent call last):
File "/home/pi/Desktop/Projects/FyleCript/Dev Files/encryption.py", line 77, in <module>
encrypt(SHA256.new(password.encode('utf-8')).digest(), str(Tfiles))
File "/home/pi/Desktop/Projects/FyleCript/Dev Files/encryption.py", line 17, in encrypt
encryptor = AES.new(key, AES.MODE_CBC, IV)
File "/usr/lib/python3/dist-packages/Crypto/Cipher/AES.py", line 94, in new
return AESCipher(key, *args, **kwargs)
File "/usr/lib/python3/dist-packages/Crypto/Cipher/AES.py", line 59, in __init__
blockalgo.BlockAlgo.__init__(self, _AES, key, *args, **kwargs)
File "/usr/lib/python3/dist-packages/Crypto/Cipher/blockalgo.py", line 141, in __init__
self._cipher = factory.new(key, *args, **kwargs)
ValueError: IV must be 16 bytes long
代码:
#-*- coding:utf-8 -*-
#Python
from Crypto.Hash import SHA256
from Crypto.Cipher import AES
import os, random, sys, pkg_resources
def encrypt(key, filename):
chunksize = 64 * 1024
outFile = os.path.join(os.path.dirname(filename), "(encrypted)"+os.path.basename(filename))
filesize = str(os.path.getsize(filename)).zfill(16)
IV = ''
for i in range(16):
IV += chr(random.randint(0, 0xFF))
encryptor = AES.new(key, AES.MODE_CBC, IV)
with open(filename, "rb") as infile:
with open(outFile, "wb") as outfile:
outfile.write(filesize)
outfile.write(IV)
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
elif len(chunk) % 16 !=0:
chunk += ' ' * (16 - (len(chunk) % 16))
outfile.write(encryptor.encrypt(chunk))
def decrypt(key, filename):
outFile = os.path.join(os.path.dirname(filename), os.path.basename(filename[11:]))
chunksize = 64 * 1024
with open(filename, "rb") as infile:
filesize = infile.read(16)
IV = infile.read(16)
decryptor = AES.new(key, AES.MODE_CBC, IV)
with open(outFile, "wb") as outfile:
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
outfile.write(decryptor.decrypt(chunk))
outfile.truncate(int(filesize))
def allfiles():
allFiles = []
for root, subfiles, files in os.walk(os.getcwd()):
for names in files:
allFiles.append(os.path.join(root, names))
return allFiles
choice = input("Do you want to (E)ncrypt or (D)ecrypt? ")
password = input("Enter the password: ")
encFiles = allfiles()
if choice in ("E", "e"):
for Tfiles in encFiles:
if os.path.basename(Tfiles).startswith("(encrypted)"):
print("%s is already encrypted" %str(Tfiles))
pass
elif Tfiles == os.path.join(os.getcwd(), sys.argv[0]):
pass
else:
encrypt(SHA256.new(password.encode('utf-8')).digest(), str(Tfiles))
print("Done encrypting %s" %str(Tfiles))
os.remove(Tfiles)
elif choice in ("D", "d"):
filename = input("Enter the filename to decrypt: ")
if not os.path.exists(filename):
print("The file does not exist")
sys.exit()
elif not filename.startswith("(encrypted)"):
print("%s is already not encrypted" %filename)
sys.exit()
else:
decrypt(SHA256.new(password.decode('utf-8')).digest(), filename)
print("Done decrypting %s" %filename)
os.remove(filename)
else:
print("Please choose a valid command.")
sys.exit()
任何帮助将不胜感激。
答案 0 :(得分:3)
好吧,让我们看一下IV
可能包含的内容:
IV = ''
for i in range(16):
IV += chr(random.randint(0, 0xFF))
让我们看看range(0, 0xff)
中的一个字符消耗了多少字节:
>>> [len(chr(i).encode()) for i in range(0, 0xff)]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2,
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2]
这是问题的根源:您假设每个字符长一个个字节,但这不是事实。
您可以使用以下代码生成N个字节的随机IV:
import os
N = 16
IV = os.urandom(N)
代码中的另一个问题是,您以'rb'
模式打开所有文件,该模式代表“读取二进制文件”,但尝试向其中写入str
实例,例如您的{ {1}}。那是行不通的,因为在这种模式下,您只能读写IV
,而不能读写bytes
。在我计算str
的解决方案中,这个问题完全消失了。
答案 1 :(得分:1)
您尚未将GetSession()
字符串转换为字节字符串。在Python 3中,IV
不是字节字符串,而是字符串。 str
摆脱了如何将字符表示为字节的概念。
您需要将您的str
变量(也许我没有检查过其他变量)转换为IV
的实例。在Python 3中创建字节串也容易一些。
bytes