我使用此代码来编码和压缩文本。但这不能正常工作:
Traceback (most recent call last): File "E:\SOUND.py", line 114, in <module>
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
TypeError: a bytes-like object is required, not 'str'
你能帮我吗?
import zlib,gzip
def str2hex(s):
return binascii.hexlify(bytes(str.encode(s)))
def hex2str(h):
return binascii.unhexlify(h)
hexstring = input()
if len(hexstring) > 200:
hexstring = str(zlib.compress(hexstring.encode('utf-8')))
print(hexstring)
hexstring = str2hex(hexstring)
ph = str(hexstring.decode('utf-8'))
print(ph)
#decompressing text
unhexsring = hex2str(hexstring).decode('utf8')
if 'x' in str(unhexsring):
print('compressed')
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
print(unhexsring)
此代码不会解压缩zlib压缩的文本。
因此编码工作良好。
我的麻烦是,当我获得编码的字符串并对其进行压缩时,我无法对其进行解压缩。 应该如何工作:
1>s = input('some text')
2>if len(s) > 200: s = str(zlib.compress(s.encode('utf-8')))
3>encoding it with str2hex()
4>decode it with hex2str()
5>str(zlib.decompress(unhexs).encode('utf8')) <---------- HERE
我无法正确解压缩,因为得到了这个:
下一个控制台转储
Python 3.7.0 (v3.7.0:1bf9cc5093, Jun 27 2018, 04:06:47) [MSC v.1914 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>>
========================= RESTART: E:\SOUND.py =========================
dghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjghdghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjghdghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjghdghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjgh
b'x\x9c\xed\x8d\xb1\r\xc0@\x08\x03\x97\xb5\xb0e\x7f\x87\xb2\x7f\x9eO\x93\x05\xd2\xa5\x02\x1d>\x0cj\x05W\xab\x18\xa3K\\\xb1\x1aE\x0b\x9d\xb2\x98\x83\xf7\xf5dz\x86\xb3#q\x8d<\x84\x8fc\n\xe9Q^0C\xe7\x13\x15\xcc\xfe7~\xd0x\x03\x88\x05\xbb\x9d'
6227785c7839635c7865645c7838645c7862315c725c786330405c7830385c7830335c7839375c7862355c786230655c7837665c7838375c7862325c7837665c7839654f5c7839335c7830355c7864325c7861355c7830325c7831643e5c7830636a5c783035575c7861625c7831385c7861334b5c5c5c7862315c783161455c7830625c7839645c7862325c7839385c7838335c7866375c786635647a5c7838365c78623323715c7838643c5c7838345c783866635c6e5c786539515e30435c7865375c7831335c7831355c7863635c786665377e5c786430785c7830335c7838385c7830355c7862625c78396427
compressed
Traceback (most recent call last):
File "E:\SOUND.py", line 114, in <module>
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
TypeError: a bytes-like object is required, not 'str'
答案 0 :(得分:5)
您在这里看到的异常:
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
TypeError: a bytes-like object is required, not 'str'
之所以提出是因为zlib.decompress
期望bytes
。更改即可轻松解决
unhexsring = hex2str(hexstring).decode('utf8') # -> str
到
unhexsring = hex2str(hexstring) # -> bytes
但这会导致新的错误:
unhexsring = zlib.decompress(unhexsring)
zlib.error: Error -3 while decompressing data: incorrect header check
发生这一行是因为此行:
hexstring = str(zlib.compress(hexstring.encode('utf-8')))
在str
实例上调用bytes
不会将bytes
转换为str
,而是将字节的repr
转换为str
>>> bs = 'Hello World'.encode('utf-8')
>>> print(repr(bs))
b'Hello World'
>>> s = str(bs)
>>> print(repr(s))
"b'Hello World'" # <- note the b....
str
转换在压缩数据的前面插入了一个“ b”,从而破坏了标题。现在让我们将十六进制字符串保留为字节对象
hexstring = zlib.compress(hexstring.encode('utf-8'))
但是现在代码引发了另一个异常:
return binascii.hexlify(bytes(str.encode(s)))
TypeError: descriptor 'encode' requires a 'str' object but received a 'bytes'
s
现在是一个bytes
对象,因此无需尝试对其进行转换(请注意,str.encode
无论如何都会返回bytes
,因此bytes
即使s
是字符串,调用也将是多余的。
所以str2hex
变成
def str2hex(s):
return binascii.hexlify(s)
现在又引发了另一个错误:
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
AttributeError: 'bytes' object has no attribute 'encode'
zlib.decompress
的输出是一个bytes
对象,因此它已经被编码(假设它是一个字符串开头)。您想对其进行解码以获得str
:
unhexsring = zlib.decompress(unhexsring).decode('utf8')
这是您的代码的一个版本,可以从命令提示符处作为脚本运行:
import binascii
import random
import string
import zlib,gzip
import zlib,gzip
def str2hex(s):
return binascii.hexlify(s)
def hex2str(h):
return binascii.unhexlify(h)
def main():
# I don't want to type 200+ chars to test this :-)
hexstring = ''.join(random.choice(string.ascii_letters) for _ in range(201))
if len(hexstring) > 200:
hexstring = zlib.compress(hexstring.encode('utf-8'))
print(hexstring)
hexstring = str2hex(hexstring)
ph = str(hexstring.decode('utf-8'))
print(ph)
#decompressing text
unhexsring = hex2str(hexstring)
if 'x' in str(unhexsring):
print('compressed')
unhexsring = zlib.decompress(unhexsring).decode('utf8')
print(unhexsring)
if __name__ == '__main__':
main()
答案 1 :(得分:0)
一个非常有趣的问题,我认为您应该摆脱这个问题
hexstring = input()
带有代码的简单示例
>>> s ='Vladimir'
>>> str.encode(s)
b'Vladimir'
>>> bytes(str.encode(s))
b'Vladimir'
>>> binascii.hexlify(bytes(str.encode(s)))
b'566c6164696d6972'
>>> binascii.unhexlify(b'566c6164696d6972')
b'Vladimir'
>>> import zlib,gzip
>>> hexstring = str(zlib.compress(s.encode('utf-8')))
>>> type (hexstring)
<class 'str'>
>>> type (s)
<class 'str'>