Question

我试图将“ x”添加到间隔“ a”和“ b”之间的列表“ arr”中。该列表已更新了'm'次。（即）我们在间隔'a'和'b'之间将'x'添加到了'm'次。仅设法在'arr'中更新了'x'值在'a'和'b'处而不是在间隔之间。请帮忙！

def main():
arr=[]
n=int(input())
m=int(input())
for i in range(n):
    arr.append(0)
for i in range(m):
    a=int(input())
    b=int(input())
    x=int(input())
    for j,c in range(len(arr)):
            if j==a-1 :
                arr[a-1]=x+arr[a-1]
            if j==b-1:
                arr[b-1]=x+arr[b-1]


    print(arr)
if __name__ == '__main__':
main()

Answer 1

我不清楚这个问题，但是我认为您要说的是：

创建数组
在数组的索引中添加数字“ x”
重复步骤2

我忽略了'm'。

  arr = []
  array_length = int(input('Length of initial array >'))
  arr = [0]*array_length # Create the array
  keep_running = True # Replacing the use of 'm' - less parameters for the user!
  while keep_running:

    x = int(input('Number to add >'))
    param_index_start = int(input('Start at index >')) #formerly 'a'
    # Lets check that the start index is valid
    if param_index_start > len(arr):
      print("Start index must be less than initial array length ({})".format(len(arr)))
      continue
    param_index_stop = int(input('Finish at index >')) #formerly 'b'

    arr_length = len(arr)
    # Lets make sure we are not trying to access indexes which do not exist
    stop_index = min(arr_length, param_index_stop)
    start_index = min(arr_length, param_index_start)
    print("Adding {} to indexes {} to {}".format(x, start_index, stop_index))
    # Do the addition
    for index in range(start_index, stop_index):
      arr[index] += x

    print("Current array: ", arr)
    # Allow the user an opportunity to exit
    continue = input("Continue adding? Y/N >")
    if continue == "N":
      keep_running = False

这是一些示例输出（压缩为空格）

Length of initial array > 10
Number to add > 1
Start at index > 5
Finish at index > 10
Adding 1 to indexes 5 to 10
Current array:  [0, 0, 0, 0, 0, 1, 1, 1, 1, 1]
Continue adding? Y/N > Y

Number to add > 3
Start at index > 4
Finish at index > 7
Adding 3 to indexes 4 to 7
Current array:  [0, 0, 0, 0, 3, 4, 4, 1, 1, 1]
Continue adding? Y/N > Y

Number to add > 1
Start at index > 0
Finish at index > 20
Adding 1 to indexes 0 to 10
Current array:  [1, 1, 1, 1, 4, 5, 5, 2, 2, 2]
Continue adding? Y/N > N

[1, 1, 1, 1, 4, 5, 5, 2, 2, 2]

您可以找到repl示例here

我可能误解了你的问题。

以给定的间隔将数字添加到列表中

1 个答案: