Question

我想检索我发送给XMPP中某人的最后一条消息。
我已经编写了这段代码，但它会提取所有已发送的消息：

let query = try? XMLElement(xmlString: "<query xmlns='urn:xmpp:mam:2'/>")
let iq = XMLElement.element(withName: "iq") as? XMLElement
iq?.addAttribute(withName: "type", stringValue: "set")
iq?.addAttribute(withName: "from", stringValue: "f.talebi@x.ir")
iq?.addAttribute(withName: "max", stringValue: "1")
iq?.addAttribute(withName: "id", stringValue: "GetLastUserMessage")


if let aQuery = query {
     iq?.addChild(aQuery)
}

xmppStream.send(iq!)

Answer 1

首先，您应该具有xmppMessageArchiveManagement模块：

var xmppMAM: XMPPMessageArchiveManagement!

然后激活它

xmppMAM.activate(xmppStream)

之后，您可以使用xmppMessageArchiveManagementDelegate的协议功能

extension someClass: XMPPMessageArchiveManagementDelegate { func xmppMessageArchiveManagement(_ xmppMessageArchiveManagement: XMPPMessageArchiveManagement, didReceiveMAMMessage message: XMPPMessage) { } func xmppMessageArchiveManagement(_ xmppMessageArchiveManagement: XMPPMessageArchiveManagement, didFinishReceivingMessagesWith resultSet: XMPPResultSet) { } }

现在您可以创建数据包并发送它们，以上两个功能将捕获服务器的数据包：警告：您应该使用mam：1而不是mam：2，并对所有检索任务使用messageArchiveManagement。例如：对于检索最后一条消息，请构建此数据包并使用mam进行发送。

`let value = DDXMLElement(name: "value", stringValue: youJid)
 let child = DDXMLElement(name: "field")
 child.addChild(value)
 child.addAttribute(withName: "var", stringValue: "with")
 let set = XMPPResultSet(max: 1, before: "")
 xmppMam.retrieveMessageArchive(at: nil, withFields: [child], with: set)`

如何使用xmppframework在XMPP中从我自己检索最后发送的消息？

1 个答案: