Question

我正在iphone中使用XMPP Framework创建聊天应用程序。我可以收到消息，但我无法发送消息。谁能给我解决这个问题？

Answer 1

- (void)sendMessage:(NSString *)msgContent
{

    NSString *messageStr = textField.text;

    if([messageStr length] > 0)
    {
        NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
        [body setStringValue:messageStr];

        NSXMLElement *message = [NSXMLElement elementWithName:@"message"];
        [message addAttributeWithName:@"type" stringValue:@"chat"];
        [message addAttributeWithName:@"to" stringValue:[jid full]];
        [message addChild:body];

        [xmppStream sendElement:message];



    }
}

在你的chatViewcontroller中使用上面的代码..对我来说工作正常。

Answer 2

试试这个：

XMPPUserCoreDataStorage *user = [[self fetchedResultsController] objectAtIndexPath:indexPath];

NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
[body setStringValue:strSendMsg];

NSXMLElement *message = [NSXMLElement elementWithName:@"message"];
[message addAttributeWithName:@"type" stringValue:@"chat"];
[message addAttributeWithName:@"to" stringValue:[user.jid full]];
[message addChild:body];

[[self xmppStream] sendElement:message];

Answer 3

如果您使用的是xmpp iPhone示例应用程序......您可以使用以下内容，它应该让您入门：

NSString *msgText = @"test reply";

XMPPMessage* msg = [[XMPPMessage alloc] initWithType:@"chat" to:[XMPPJID jidWithString:displayName]];
[msg addBody:msgText];

[_xmppStream sendElement:msg];

将它放在

中xmppStream委托方法中的警告下方

<强> iPhoneXMPPAppDelegate.m：

-(void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message

这会自动将“测试回复”发送回最初向您发送消息的jid

glhf！

Answer 4

斯威夫特3回答：

let user = XMPPJID(string: "user@example.com")
let msg = XMPPMessage(type: "chat", to: user)
msg?.addBody("test message")
self.xmppStream.send(msg)

如何使用XMPP Framework发送消息

4 个答案: