Question

说我在列表中有一个列表，该列表包含在列表中。例如：

foo = [[[2, 2, 2], [1, 1, 1], [3, 3, 3]], [[2, 2, 2], [1, 1, 1], [3, 3, 3]]]

我想按顺序对其进行排序：

foo = [[[1, 1, 1], [2, 2, 2], [3, 3, 3]], [[1, 1, 1], [2, 2, 2], [3, 3, 3]]]

我可以使用[sorted(i) for i in foo]实现这一目标。但是，有什么方法可以对列表进行排序而无需理解列表（或创建新列表）？

列表本身中的值将更改，但无需排序。

我尝试过的所有方法都归结为与上述相同的方法。

Answer 1

如果要避免创建新列表，则只需遍历列表并调用.sort()

>>> foo = [[[2, 2, 2], [1, 1, 1], [3, 3, 3]], [[2, 2, 2], [1, 1, 1], [3, 3, 3]]]

for i in foo:
    i.sort()

>>> foo                                                                         
[[[1, 1, 1], [2, 2, 2], [3, 3, 3]], [[1, 1, 1], [2, 2, 2], [3, 3, 3]]]

Answer 2

如果您不介意创建新列表，该如何使用import android.os.AsyncTask; import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.net.HttpURLConnection; import java.net.MalformedURLException; import java.net.URL; public class fetchData extends AsyncTask<Void,Void,Void> { String data =""; String dataParsed =""; String singleParsed=""; @Override protected Void doInBackground(Void... voids) { try { URL url = new URL("https://itunes.apple.com/search?term="+MainActivity.searchValue+"&entity="+MainActivity.entityValue); HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection(); InputStream inputStream = httpURLConnection.getInputStream(); BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream)); StringBuilder sb = new StringBuilder(); String line = null; while((line = bufferedReader.readLine()) != null){ sb.append(line + "\n"); data = data + line; } JSONArray JA = new JSONArray(data); for (int i = 0; i < JA.length(); i++) { JSONObject JO = (JSONObject) JA.get(i); singleParsed = " " +JO.get("trackName"); dataParsed = dataParsed + singleParsed; } } catch (MalformedURLException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (JSONException e) { e.printStackTrace(); } return null; } @Override protected void onPostExecute(Void aVoid) { super.onPostExecute(aVoid); MainActivity.data.setText(this.dataParsed); } }函数：

import android.support.v7.app.AlertDialog;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Spinner;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

Button submit;
public static TextView data;
public static String searchValue ="";
public static String entityValue ="";
public Spinner spinner;
public static final String[]paths = {"Music","Movie","Software"};
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    //Setup Spinner
    spinner = (Spinner) findViewById(R.id.spinner);
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(MainActivity.this,android.R.layout.simple_spinner_dropdown_item,paths);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);

    //Setup Button, Textview, and EditText
    submit = (Button) findViewById(R.id.button);
    data = (TextView) findViewById(R.id.textView);
    final EditText searchText = (EditText) findViewById(R.id.searchEditText);

    submit.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            searchValue = searchText.getText().toString();
            if(spinner.getSelectedItem().equals("Music")){
                entityValue = "musicTrack";
            }else if(spinner.getSelectedItem().equals("Movie")){
                entityValue="movie";
            }else if(spinner.getSelectedItem().equals("Software")){
                entityValue="software";
            }

            System.out.println(entityValue);
            fetchData process = new fetchData();
            process.execute();
        }
    });
}
}

对列表中的列表列表进行排序

2 个答案: