角度代码为::
app.component.ts
Json数据
this.objsearch=[{ "Key": "FirstName", "value": this.firstName },
{ "Key": "MiddleName", "value": this.middleName },
{ "Key": "fatherName ", "value": this.fatherName },
{ "Key": "motherName", "value": this.motherName },
{ "Key": "_UId", "value": this._UId },
{ "Key": "Country", "value": this.ddlcountry },
{ "Key": "State", "value": this.ddlState },
{ "Key": "City", "value": this.ddlCity },
]
调用service.ts的方法
this.ServiceObject.saveData(Json.Strigify(this.objsearch)).subscribe(response => (this._param) = response);
Service.ts
public_saveDataURL="http://localhost:53915/api/ComapnyAndProduct/DeleteItem";
方法::
saveData(objSearch: any)
{
return this._http.post(this._saveDataURL,objSearch)
.map((response: Response) => response.json());
}
网络Api方法
[HttpPost]
public IHttpActionResult DeleteItem([FromUri]Mregistration objSearch)
{
return Ok();
}
答案 0 :(得分:0)
您无需在JSON.strigify(this.objsearch)
处使用saveData
。
this.ServiceObject.saveData(this.objsearch).subscribe(response => (this._param) = response);
此外,您需要从正文而不是从网址获取数据。
[HttpPost]
public IHttpActionResult DeleteItem([FromBody]Mregistration objSearch)
{
return Ok();
}
您的对象必须具有这样的结构
this.objsearch = {
firstName: this.firstName,
middleName: this.middleName,
fatherName: this.fatherName,
motherName: this.matherName,
_Uid: this._Uid,
country: this.ddlcountry,
state: this.ddlState,
city: this.ddlCity
}