Question

请帮助解决这个问题。我有一个看起来像这样的对象：

data: {
       offersMonday: [
               {
                 "name": "name1",
                 "description" "description 1"
               },
               {
                 "name": "name2",
                 "description": "description 2"
               }
          ],
        offersTuesday: [
        {
                 "name": "name1",
                 "description" "description 1"
               },
               {
                 "name": "name2",
                 "description": "description 2"
               }
          ],
          offersWednesday: [
             {
                 "name": "name1",
                 "description" "description 1"
               },
               {
                 "name": "name2",
                 "description": "description 2"
               }
          ]
}

我需要在每个对象的实例下获取描述。做这个的最好方式是什么？

我应该使用filter()功能吗？

感谢。

编辑：我需要将它们全部放在一个变量中。所以做offersMonday[0].description + offersTuesday[0].description这样的事情并不是一件好事。

Answer 1

您可以尝试这样的事情：

as

阅读具体说明。或类似以下内容获取所有描述：

＆＃13;

data.offersMonday[0].description

＆＃13;

Answer 2

var descs=[];
for(key in data){
  descs=descs.concat(data[key].map(el=>el.description));
}
console.log(descs);//array
console.log(descs.join(","));//string

遍历主Object，获取所有数组elems描述值，并将它们附加到descs数组。

Answer 3

你可以尝试类似的东西：

SELECT (CASE WHEN (SELECT SubjectName FROM subjects) LIKE '%History%'      
             THEN (SELECT SubjectsID FROM Subjects)
             ELSE intSubjectID
        END)

Answer 4

看起来你错过了一些:标记来正确格式化，我已经重新格式化了以下输入数据：

const input = {
data: {
    offersMonday: [{
        name: "name1",
        description: "description 1"
    }, {
        name: "name2",
        description: "description 2"
    }],
    offersTuesday: [{
        name: "name1",
        description: "description 1"
    }, {
        name: "name2",
        description: "description 2"
    }],
    offersWednesday: [{
        name: "name1",
        description: "description 1"
    }, {
        name: "name2",
        description: "description 2"
    }]
}
}

下面是一个移动对象并抓住你需要的功能。我删除了“”标记，因为它们不是有效的JS（我假设你从JSON获得了这个）。当JSON对象进来时，无论如何它都会为你删除引号。

这是适用于我的解决方案，如果格式不是您想要的，请告诉我。

function groupDescriptions(input) {
  let aggregatedArray = [];
  const data = input.data;

  for (day in data) {
      const innerArray = data[day];
      innerArray.forEach((item) => {
          aggregatedArray.push(item.description);
      })

  }
    return aggregatedArray;
  }

aggregatedArray会返回此信息：

[ 'description 1',
'description 2',
'description 1',
'description 2',
'description 1',
'description 2' ]

如何从此对象获取数据？

4 个答案: