Question

我正在使用代码，尝试将参数发送到服务器时收到此错误。

com.android.volley.VolleyError: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()

然后我尝试将Looper.prepare（）添加到代码中，现在当我按下按钮时应用程序崩溃。我正在使用QR阅读器获取textview，然后将其发送回服务器的某些部分，然后程序的其他部分也将发送给服务器。这只是我发送数据时的一部分。我也正在获取位置，并使用了微调框和edittext字段。

这是我的代码...

 send.setOnClickListener(new View.OnClickListener() {


        @Override
        public void onClick(View v) {

 Toast.makeText(QRCODEPAGE1.this, "Make it work", Toast.LENGTH_SHORT).show();
           // Intent meow = new Intent(QRCODEPAGE1.this, QRLASTPAGE.class);
           // startActivity(meow);

            Toast.makeText(QRCODEPAGE1.this, "Started", 
 Toast.LENGTH_SHORT).show();
            RequestQueue mRequestQueue = 
 Volley.newRequestQueue(QRCODEPAGE1.this);
            String url = "http://api- 
 dev.eportfolioapi.com/api/sensor/install";
            Cache cache = new DiskBasedCache(getCacheDir(), 1024*1024);
            Network network = new BasicNetwork(new HurlStack());
            //Looper.prepare();
            //mRequestQueue = new RequestQueue(cache, network);
            Toast.makeText(QRCODEPAGE1.this, "DONE", 
 Toast.LENGTH_SHORT).show();

            StringRequest request = new StringRequest(Request.Method.POST, 
  url, new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {
  Toast.makeText(QRCODEPAGE1.this, "you passed", Toast.LENGTH_SHORT).show();
        System.out.println(response.toString());
    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {
 //Toast.makeText(QRCODEPAGE1.this, "you failed", Toast.LENGTH_SHORT).show();
        Toast.makeText(QRCODEPAGE1.this, String.valueOf(error), 
 Toast.LENGTH_LONG).show();
        Log.e("Volley ERROR: ", error.toString());
        //Looper.prepare();
    }
}) {
    @Override
    protected Map<String, String> getParams() throws AuthFailureError {
Toast.makeText(QRCODEPAGE1.this, "Params", Toast.LENGTH_SHORT).show();
        Map<String, String> params = new HashMap<String, String>();
        params.put("userId", tvresult.getText().toString());
        Toast.makeText(QRCODEPAGE1.this, "you passed userid", 
Toast.LENGTH_SHORT).show();
        params.put("customerId", custID.toString());
        Toast.makeText(QRCODEPAGE1.this, "you passed custid", 
 Toast.LENGTH_SHORT).show();
        params.put("sensorId", tvresult.getText().toString());
        Toast.makeText(QRCODEPAGE1.this, "sensorid", 
 Toast.LENGTH_SHORT).show();
         params.put("projectId", tvresult.getText().toString());
        Toast.makeText(QRCODEPAGE1.this, "you passed proid", 
Toast.LENGTH_SHORT).show();
        params.put("sensorVendorID", tvresult.getText().toString());
        params.put("sensorGatewayId", tvresult.getText().toString());
       // params.put("qrCodeUrl", );
        params.put("lat", textLat.getText().toString());
        Toast.makeText(QRCODEPAGE1.this, "lat", Toast.LENGTH_SHORT).show();
        params.put("long", textLong.getText().toString());
        Toast.makeText(QRCODEPAGE1.this, "long", Toast.LENGTH_SHORT).show();
        params.put("locationWithinFacility", descprit.getText().toString());
        return params;

    }
};


            request.setTag(TAG);
            mRequestQueue.add(request);

我应该在哪里添加那行代码？

Answer 1

无法在未调用Looper.prepare（）异常的线程内创建处理程序的可能原因是尝试从后台线程执行与UI相关的操作。

在您的情况下，您不应该在getParams()方法中显示吐司，因为它可能是从凌空工作线程中调用的

Answer 2

onResponse和onErrorResponse在UI线程之外执行。

凌空错误：Looper.prepare（）

2 个答案: