Matplotlib熊猫plot_date颜色类别
我有一些数据框：
Date_Week Game_Order Game_Mode
0 2010-04-13 124 a
1 2010-06-29 7 a
2 2009-03-17 40 b
3 2010-08-03 54 a
4 2009-09-29 20 e
5 2009-07-07 13 b
6 2009-04-07 29 a
7 2010-03-30 37 b
8 2010-04-13 118 a
9 2010-07-13 12 b
10 2011-08-23 38 c
11 2009-06-02 96 a
12 2010-03-16 48 a
13 2010-08-10 18 b
14 2010-11-09 1 c
其中Date_Week列是日期时间时间戳：
dft['Date_Week'][0]
Out[1043]: Timestamp('2010-04-13 00:00:00')
我正在使用熊猫plot_date()函数进行绘制。
import matplotlib.pyplot as plt
import seaborn as sns
import matplotlib as mpl
fig, ax = plt.subplots(figsize=(22,8))
ax.plot_date(dft['Date_Week'], dft['Game_Order'], marker='o', markersize=2, mew=2)
ax.tick_params('y', colors='k')
ax.set_xlabel('Date')
ax.set_ylabel('Frequency')
ax.set_title('Weekly Games')
ax.tick_params('y', colors='k')
ax.grid(b=True, which='major', color='w', linewidth=1.0)
ax.grid(b=True, which='minor', color='w', linewidth=0.5)
ax.yaxis.grid(True)
xtick_locator = mpl.dates.MonthLocator(interval=6)
xtick_formatter = mpl.dates.AutoDateFormatter(xtick_locator)
ax.xaxis.set_major_locator(xtick_locator)
ax.xaxis.set_major_formatter(xtick_formatter)
xtick_locator = mpl.dates.MonthLocator(bymonth=[2,3,4,5,6,8,9,10,11,12], interval=1)
xtick_formatter = mpl.dates.AutoDateFormatter(xtick_locator)
ax.xaxis.set_minor_locator(xtick_locator)
ax.xaxis.set_minor_formatter(xtick_formatter)
plt.setp(ax.xaxis.get_minorticklabels(), rotation=90, size=10)
plt.setp(ax.xaxis.get_majorticklabels(), rotation=90, size=15)
fig.subplots_adjust(bottom=0.24)
plt.legend()
plt.show()
这给出了：
我想根据Game_Mode列中的类别为点着色。
我做了一些研究，发现了this，this，this和this。
基于此，我尝试了以下每个操作：根据类别将浮点数，seaborn RGB调色板值或特定颜色映射到颜色列：
# Colouring
categories = dft['Game_Mode'].unique()
# Possible Way 1
colors = np.linspace(0, 1, len(categories))
colordict = dict(zip(categories, colors))
# Possible Way 2
colors = sns.color_palette()
colordict_1 = dict(zip(categories, colors))
# Possible Way 3
colors = ['r', 'g', 'b', 'c' ,'k']
colordict_2 = dict(zip(categories, colors))
dft["Colour"] = dft['Game_Mode'].apply(lambda x: colordict[x])
dft["Colour_1"] = dft['Game_Mode'].apply(lambda x: colordict_1[x])
dft["Colour_2"] = dft['Game_Mode'].apply(lambda x: colordict_2[x])
dft
Date_Week Game_Order Game_Mode Colour \
0 2010-04-13 124 a 0.000000
1 2010-06-29 7 a 0.000000
2 2009-03-17 40 b 0.333333
3 2010-08-03 54 a 0.000000
4 2009-09-29 20 e 0.666667
5 2009-07-07 13 b 0.333333
6 2009-04-07 29 a 0.000000
7 2010-03-30 37 b 0.333333
8 2010-04-13 118 a 0.000000
9 2010-07-13 12 b 0.333333
10 2011-08-23 38 c 1.000000
11 2009-06-02 96 a 0.000000
12 2010-03-16 48 a 0.000000
13 2010-08-10 18 b 0.333333
14 2010-11-09 1 c 1.000000
Colour_1 Colour_2
0 (0.298039215686, 0.447058823529, 0.690196078431) r
1 (0.298039215686, 0.447058823529, 0.690196078431) r
2 (0.333333333333, 0.658823529412, 0.407843137255) g
3 (0.298039215686, 0.447058823529, 0.690196078431) r
4 (0.76862745098, 0.305882352941, 0.321568627451) b
5 (0.333333333333, 0.658823529412, 0.407843137255) g
6 (0.298039215686, 0.447058823529, 0.690196078431) r
7 (0.333333333333, 0.658823529412, 0.407843137255) g
8 (0.298039215686, 0.447058823529, 0.690196078431) r
9 (0.333333333333, 0.658823529412, 0.407843137255) g
10 (0.505882352941, 0.447058823529, 0.698039215686) c
11 (0.298039215686, 0.447058823529, 0.690196078431) r
12 (0.298039215686, 0.447058823529, 0.690196078431) r
13 (0.333333333333, 0.658823529412, 0.407843137255) g
14 (0.505882352941, 0.447058823529, 0.698039215686) c
但是，当我尝试使用任何Colour列进行绘图时，出现以下错误：
0：
# Colour error
fig, ax = plt.subplots(figsize=(22,8))
ax.plot_date(dft['Date_Week'], dft['Game_Order'], marker='o', markersize=2, mew=2, c=dft['Colour'])
Out[1058]: [<matplotlib.lines.Line2D at 0x289091d0>]Traceback (most recent call last):
File "path\Anaconda3\lib\site-packages\IPython\core\formatters.py", line 307, in __call__
return printer(obj)
File "C:\Users\p\Anaconda3\lib\site-packages\IPython\core\pylabtools.py", line 240, in <lambda>
png_formatter.for_type(Figure, lambda fig: print_figure(fig, 'png', **kwargs))
File "C:\Users\p\Anaconda3\lib\site-packages\IPython\core\pylabtools.py", line 124, in print_figure
fig.canvas.print_figure(bytes_io, **kw)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\backend_bases.py", line 2200, in print_figure
**kwargs)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\backends\backend_agg.py", line 545, in print_png
FigureCanvasAgg.draw(self)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\backends\backend_agg.py", line 464, in draw
self.figure.draw(self.renderer)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\artist.py", line 63, in draw_wrapper
draw(artist, renderer, *args, **kwargs)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\figure.py", line 1144, in draw
renderer, self, dsu, self.suppressComposite)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\image.py", line 139, in _draw_list_compositing_images
a.draw(renderer)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\artist.py", line 63, in draw_wrapper
draw(artist, renderer, *args, **kwargs)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\axes\_base.py", line 2426, in draw
mimage._draw_list_compositing_images(renderer, self, dsu)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\image.py", line 139, in _draw_list_compositing_images
a.draw(renderer)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\artist.py", line 63, in draw_wrapper
draw(artist, renderer, *args, **kwargs)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\lines.py", line 828, in draw
rgbaFace = self._get_rgba_face()
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\lines.py", line 1340, in _get_rgba_face
rgbaFace = mcolors.to_rgba(facecolor, self._alpha)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\colors.py", line 143, in to_rgba
rgba = _to_rgba_no_colorcycle(c, alpha)
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\colors.py", line 198, in _to_rgba_no_colorcycle
raise ValueError("RGBA sequence should have length 3 or 4")
ValueError: RGBA sequence should have length 3 or 4
<matplotlib.figure.Figure at 0x2c4705c0>
1
# Colour_1 error:
...
File "C:\Users\p\Anaconda3\lib\site-packages\matplotlib\colors.py", line 194, in _to_rgba_no_colorcycle
raise ValueError("Invalid RGBA argument: {!r}".format(orig_c))
ValueError: Invalid RGBA argument: 0 (0.298039215686, 0.447058823529, 0.690196078431)
2
# Colour 2 error:
...
File "C:\Users\p\Anaconda3\lib\site-packages\pandas\core\generic.py", line 2970, in __getattr__
return object.__getattribute__(self, name)
AttributeError: 'Series' object has no attribute 'lower'
<matplotlib.figure.Figure at 0x29ec9dd8>
我已经搜索了这些错误，并提出了以下问题：
https://github.com/matplotlib/matplotlib/issues/7603 https://github.com/matplotlib/matplotlib/issues/6266/ https://github.com/matplotlib/matplotlib/issues/2148 Setting colors using color cycle on date plots using `plot_date()`
这些表明这可能与plot_date有关，但是建议的选项均无效。
有人可以告诉我如何解决吗？
1 个答案:
答案 0 :(得分：1)
为了李艾莎的利益：
根据@ImportanceOfBeingErnest的回答，我必须针对每种游戏类型和游戏顺序进行单独绘制。
我不得不扩展创建游戏顺序列的方式，而不是进行global order计算每种游戏子类型的顺序。这意味着必须创建新列"Game_Order_a" "Game_order_b"等，这些列仅具有对应于该game_mode的行的值，并且在其他任何地方都具有NaN（即仅具有特定的游戏类型）。
然后，这意味着分别绘制数据的子集并 手动设置Seaborn分配颜色 。这些颜色由图例处理程序拾取：
因此，对于5个不同的Game_Mode，我这样做了：
fig, ax = plt.subplots()
# Subset your data by choosing where Game_Mode = 'a'
ax.plot_date(df[df['Game_Mode'] == 'a']['Date_Week_a'], df[df['Game_Mode'] == 'a']['Game_Order_a'], marker='o', markersize=2, mew=2, label='a')
ax.plot_date(df[df['Game_Mode'] == 'b']['Date_Week_b'], df[df['Game_Mode'] == 'b']['Game_Order_b'], marker='o', markersize=2, mew=2, label='b')
# ... etc for each type that you have
plt.legend(fontsize=15, markerscale=4)
plt.show()
这会为您提供每种类型的图，并自动选择颜色。如果您愿意使用c=参数，可以指定它们，但对我而言不是必需的。
相关问题
最新问题
- 我写了这段代码，但我无法理解我的错误
- 我无法从一个代码实例的列表中删除 None 值，但我可以在另一个实例中。为什么它适用于一个细分市场而不适用于另一个细分市场？
- 是否有可能使 loadstring 不可能等于打印？卢阿
- java中的random.expovariate()
- Appscript 通过会议在 Google 日历中发送电子邮件和创建活动
- 为什么我的 Onclick 箭头功能在 React 中不起作用？
- 在此代码中是否有使用“this”的替代方法？
- 在 SQL Server 和 PostgreSQL 上查询，我如何从第一个表获得第二个表的可视化
- 每千个数字得到
- 更新了城市边界 KML 文件的来源？