我有两个/**
* {@link EnableAutoConfiguration Auto configuration} for testing mail service
* connectivity on startup.
*
* @author Eddú Meléndez
* @author Stephane Nicoll
* @since 1.3.0
*/
@Configuration
@AutoConfigureAfter(MailSenderAutoConfiguration.class)
@ConditionalOnProperty(prefix = "spring.mail", value = "test-connection")
@ConditionalOnSingleCandidate(JavaMailSenderImpl.class)
public class MailSenderValidatorAutoConfiguration {
private final JavaMailSenderImpl mailSender;
public MailSenderValidatorAutoConfiguration(JavaMailSenderImpl mailSender) {
this.mailSender = mailSender;
}
@PostConstruct
public void validateConnection() {
try {
this.mailSender.testConnection();
}
catch (MessagingException ex) {
throw new IllegalStateException("Mail server is not available", ex);
}
}
}
，它们表示地图上的可见坐标区域/框。它们是NE角和SW角。
CLLocationCoordinate2D如何数学地转换这两个坐标以找到NW和SE坐标/角？
答案 0 :(得分：1)
难道不能只是从每个坐标中拉出等效点并以自己的方式组合它们吗？
neCoordinate.latitude（东部）和swCoordinate.longitude（南部）以建立SECoordinate？
neCoordinate.longitude（北）和swCoordinate.latitude（西）来建立NWCoordinate？
aka：
CLLocationCoordinate2D seCoordinate = CLLocationCoordinate2DMake(latitude: neCoordinate.latitude, longitude: swCoordinate.longitude);
CLLocationCoordinate2D nwCoordinate = CLLocationCoordinate2DMake(latitude: swCoordinate.latitude, longitude: neCoordinate.longitude);