Question

我有一些具有以下结构的数据框：

ID| Page    |   User          |    Timestamp      |
|1|Page 1   |Ericd            |2002-09-07 19:39:55|
|1|Page 1   |Liir             |2002-10-12 03:01:42|
|1|Page 1   |Tubby            |2002-10-12 03:02:23|
|1|Page 1   |Mojo             |2002-10-12 03:18:24|
|1|Page 1   |Kirf             |2002-10-12 03:19:03|
|2|Page 2   |The Epopt        |2001-11-28 22:27:37|
|2|Page 2   |Conversion script|2002-02-03 01:49:16|
|2|Page 2   |Bryan Derksen    |2002-02-25 16:51:15|
|2|Page 2   |Gear             |2002-10-04 12:46:06|
|2|Page 2   |Tim Starling     |2002-10-06 08:13:42|
|2|Page 2   |Tim Starling     |2002-10-07 03:00:54|
|2|Page 2   |Salsa Shark      |2003-03-18 01:45:32|

，我想查找在某个时间段内（例如，每月）访问该页面的用户数量。例如，对于2002年的10个月，结果将是

|1|Page 1   |Liir             |2002-10-12 03:01:42| 
|1|Page 1   |Tubby            |2002-10-12 03:02:23|
|1|Page 1   |Mojo             |2002-10-12 03:18:24|
|1|Page 1   |Kirf             |2002-10-12 03:19:03|
|2|Page 2   |Gear             |2002-10-04 12:46:06|
|2|Page 2   |Tim Starling     |2002-10-06 08:13:42|
|2|Page 2   |Tim Starling     |2002-10-07 03:00:54|

和页数：

              numberOfUsers (in October 2002)
|1|Page 1   |      4
|2|Page 2   |      3

问题还在于如何在每年的每个月中应用此逻辑。我想出了如何查找例如最近n天的事件

days = lambda i: i * 86400
window = (Window().partitionBy(col("page"))
          .orderBy(col("timestamp").cast("timestamp").cast("long")).rangeBetween(-days(30), 0))

df = df.withColumn("monthly_occurrences", func.count("user").over(window))
df.show()

一些建议，我会感激的

Answer 1

您可以先创建包含年份-月份组合的列，然后使用该列进行分组。因此，一个可行的示例将是：

import pyspark.sql.functions as F

df = sc.parallelize([
    ('2018-06-02T00:00:00.000Z','tim', 'page 1' ),
    ('2018-07-20T00:00:00.000Z','tim', 'page 1' ),
    ('2018-07-20T00:00:00.000Z','john', 'page 2' ),
    ('2018-07-20T00:00:00.000Z','john', 'page 2' ),
    ('2018-08-20T00:00:00.000Z','john', 'page 2' )
]).toDF(("datetime","user","page" ))

df = df.withColumn('yearmonth',F.concat(F.year('datetime'),F.lit('-'),F.month('datetime')))    
df_agg = df.groupBy('yearmonth','page').count()
df_agg.show()

输出：

+---------+------+-----+
|yearmonth|  page|count|
+---------+------+-----+
|   2018-7|page 2|    2|
|   2018-6|page 1|    1|
|   2018-7|page 1|    1|
|   2018-8|page 2|    1|
+---------+------+-----+

希望这会有所帮助！

Answer 2

如果您正在寻找动态期间，请首先将日期转换为时间戳，然后减去今天的所有时间戳，然后将（整数）除以要分组的时间间隔的时间戳。下面的代码按5天的时间间隔对行进行分组。

import pyspark.sql.functions as F
from datetime import datetime

# todays timestamp
Today = datetime.today().timestamp()
# how many timestamp is today 
DAY_TIMESTAMPS = 24 * 60 * 60

df = sc.parallelize([
    ('2017-06-02 00:00:00','tim', 'page 1' ),
    ('2017-07-20 00:00:00','tim', 'page 1' ),
    ('2017-07-21 00:00:00','john', 'page 2' ),
    ('2017-07-22 00:00:00','john', 'page 2' ),
    ('2017-08-23 00:00:00','john', 'page 2' )
]).toDF(("datetime","user","page" ))

# group by five days
timeInterval = 5* DAY_TIMESTAMPS

df \
    .withColumn('timestamp', F.unix_timestamp(F.to_date('datetime', 'yyyy-MM-dd HH:mm:ss'))) \ 
    .withColumn('timeIntervalBefore', ((Today-F.col('timestamp'))/(timeInterval)).cast('integer')) \
    .groupBy('timeIntervalBefore', 'page') \
    .agg(F.count('user').alias('number of users')).show()

结果：

+------------------+------+---------------+
|timeIntervalBefore|  page|number of users|
+------------------+------+---------------+
|                70|page 2|              2|
|                80|page 1|              1|
|                70|page 1|              1|
|                64|page 2|              1|
+------------------+------+---------------+

如果您需要近似时间段的日期：

df \
    .withColumn('timestamp', F.unix_timestamp(F.to_date('datetime', 'yyyy-MM-dd HH:mm:ss'))) \
    .withColumn('timeIntervalBefore', ((Today-F.col('timestamp'))/(timeInterval)).cast('integer')) \
    .groupBy('timeIntervalBefore', 'page') \
    .agg(
        F.count('user').alias('number_of_users'), 
        F.min('timestamp').alias('FirstDay'), 
        F.max('timestamp').alias('LastDay')) \
    .select(
        'page', 
        'number_of_users', 
        F.from_unixtime('firstday').alias('firstDay'), 
        F.from_unixtime('firstday').alias('lastDay')).show()

结果：

+------+---------------+-------------------+-------------------+
|  page|number_of_users|           firstDay|            lastDay|
+------+---------------+-------------------+-------------------+
|page 2|              2|2017-07-21 00:00:00|2017-07-21 00:00:00|
|page 1|              1|2017-06-02 00:00:00|2017-06-02 00:00:00|
|page 1|              1|2017-07-20 00:00:00|2017-07-20 00:00:00|
|page 2|              1|2017-08-23 00:00:00|2017-08-23 00:00:00|
+------+---------------+-------------------+-------------------+

每次触发窗口功能

2 个答案: