Question

我有一个JSON，我想从中映射键并生成另一个JSON。在order_data中，我要打印所有子表数据，然后最后要放父表数据

以下是我从中生成JSON的函数

public function example(){
        $data = '{"details":[{"price":"4","selectedSubOptionsIds":[],"dis":"27025"},{"price":"1","selectedSubOptionsIds":[63138, 63137],"dis":"27027"}],"a":"1238","b":"2","c":"0","d":"NULL"}';
        $data = json_decode($data);
        $pz['a'] = $data->a; 
        $pz['b'] = $data->b; 
        $pz['c'] = $data->c; 
        $pz['d'] = $data->d; 
        $detailing = $data->details; //this is an array
        $j=0;

        foreach ($detailing as  $value) {

            $subOptIds = $value->selectedSubOptionsIds;  //this is an array  
            $dis = $this->db->from('parent')->where('id',$value->dis)->get()->row();
            $i=0;
            if(count($subOptIds) <= 0){
                $detail[$i]['a'] = $dis->name;
                $detail[$i]['b'] = $dis->id;
                $detail[$i]['c'] = $dis->price;
                $i++;
            } 

            else{ 
                foreach ($subOptIds as $suboptid) {
                    $subopt = $this->db->from('child')->where('id',$suboptid)->get()->row();
                    $detail[$i]['a'] = $subopt->name;
                    $detail[$i]['b'] = $subopt->id;
                    $detail[$i]['c'] = $subopt->price; 
                    $i++;
                }
            }


            $j++;
        }
        $pz['order_data'] = $detail;
        echo json_encode($pz);
     }

它向我返回json：

{
  "a": "1238",
  "b": "2",
  "c": "0",
  "d": "NULL",
  "order_data": Array[2][
    {
      "0": {
        "a": "Test Dish 1",
        "b": "27025",
        "c": "100.0"
      },
      "a": "Pepsi",
      "b": "63138",
      "c": "40.0"
    },
    {
      "a": "Cream",
      "b": "63137",
      "c": "25.0"
    }
  ]
}

但是我希望order_data数组成为单个数组，并且它仅应包含对象，并且不应包含任何嵌套数组，就像下面的

{
  "a": "1238",
  "b": "2",
  "c": "0",
  "d": "NULL",
  "order_data": Array[2][ 
    {
        "a": "Test Dish 1",
        "b": "27025",
        "c": "100.0"
    },
    {

      "a": "Pepsi",
      "b": "63138",
      "c": "40.0"
    },
    {
      "a": "Cream",
      "b": "63137",
      "c": "25.0"
    }
  ]
}

Answer 1

首先，据我所知，所显示的代码不可能产生您在问题中声明的输出-请参见https://eval.in/1032176上的演示

第二，不考虑上述内容，要获得您真正想要的输出，您只需解决一个小错误。将$i=0;移动到外部foreach外部-当前，每次循环浏览$detailing中的每个项目时，它都会重置，因此{ {1}}数组在后续循环中被覆盖。您也完全不需要0，它在任何地方都不会使用。

摘要：

$details

在https://eval.in/1032185上查看工作演示

JSON的自定义映射

1 个答案: