上下文关联:
我正在研究一种面部识别算法,NIST是一家致力于标准化所有可用算法之间的测试,测量和比较的组织。为了进行测试和比较,我需要实现它们的接口,该接口可以在FRVT Project中找到,更具体地说在frvt11.h文件中可以找到。
frvt11.h 此问题的相关代码:
namespace FRVT {
//...A lot of code defining ReturnStatus, ReturnCode, etc.
/**
* @brief
* The interface to FRVT 1:1 implementation
*
* @details
* The submission software under test will implement this interface by
* sub-classing this class and implementing each method therein.
*/
class Interface {
public:
virtual ~Interface() {}
virtual ReturnStatus
initialize(const std::string &configDir) = 0;
/**
* @brief
* Factory method to return a managed pointer to the Interface object.
* @details
* This function is implemented by the submitted library and must return
* a managed pointer to the Interface object.
*
* @note
* A possible implementation might be:
* return (std::make_shared<Implementation>());
*/
static std::shared_ptr<Interface>
getImplementation();
};
}
implementation.h 我正在开发的实现的相关代码:
#include "frvt11.h"
using namespace FRVT;
struct Implementation : public Interface {
ReturnStatus
initialize(const std::string &configDir) override;
static std::shared_ptr<Interface>
getImplementation();
};
implementation.cpp 我正在开发的实现的相关代码:
#include "implementation.h"
using namespace FRVT;
ReturnStatus
Implementation::initialize(
const std::string &configDir) {
return ReturnStatus(ReturnCode::Success," - initialize");
}
std::shared_ptr<Interface>
Implementation::getImplementation() {
return (std::make_shared<Implementation>());
}
最后我的问题:
问题:如何实现getImplementation()以便将引用的“托管指针返回到Interface对象”?
答案 0 :(得分:1)
我认为您可以执行以下操作:
std::shared_ptr<Interface> Implementation::getImplementation() {
return std::make_shared<Implementation>();
}
int main() {
auto interface = Implementation::getImplementation();
}
并且interface
的类型为std::shared_ptr<Interface>
。您可以进一步传递它。