我的数字范围是<!DOCTYPE html>
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至-100。
我正在尝试将其标准化为100到0并保留小数位数。
3我想创建一个程序函数以将任何范围标准化为任何值，例如：
http://rextester.com/ZJWNS24313
-100 = 0
-50 = 0.75
0 = 1.5
50 = 2.25
100 = 3
但是这不能提供正确的输出。
double Normalize(double val, double valmin, double min, double max)
{
return (val - valmin) / (max - min);
}
变为100，而不是66.6666666666667。
如果我将公式乘以十进制3，结果将是正确的。
0.045 = ((100 - -100) / (3 - 0)) * 0.045
3 = ((50 - -100) / (3 - 0)) * 0.045
2.25 = ((-50 - -100) / (3 - 0)) * 0.045
但是如何制作公式，这样我不必在末尾指定十进制数字？
因为如果我想将新数字从0.75标准化为0，则必须将其更改为5。
答案 0 :(得分：2)
尝试一下：
double Normalize(double val, double valmin, double valmax, double min, double max)
{
return (((val - valmin) / (valmax - valmin)) * (max - min)) + min;
}
（假设valmin和valmax为-100至100，min和max为0至3）
编辑：应在末尾加上最小值而不是减去