Question

这是我第一次在这里问一个问题（我来自亚洲）。

平台：UWP 17632

IDE：Visual Studio 2017

基于项目的重新设计，我需要将一些信息发布到网站上。

我将介绍有关How to make HTTP POST web request方法A的答案。

这是我的代码：

public async void PostDataAsync(string pTemperture, string pHumidity, string pFireStatus, string pLightStatus, string pBodyStatus)
   {
       var values = new Dictionary<string, string>
           {
               {"count", "1" },
               {"temperture_0", pTemperture },
               {"Humidity_0", pHumidity },
               {"FireStatus_0", pFireStatus },
               {"LightStatus_0" ,pLightStatus},
               {"BodyDetect_0", pBodyStatus }
           };
       var content = new FormUrlEncodedContent(values);
       try
       {
           var response = await client.PostAsync("http://115.159.36.210/api/onehome/upload", content);//Here throw an exception
           System.Diagnostics.Debug.WriteLine(response);
           var responseString = response.Content.ReadAsStringAsync();
           System.Diagnostics.Debug.WriteLine(responseString);
       }
       catch (Exception ex)
       {
           System.Diagnostics.Debug.WriteLine(ex.HelpLink);
           System.Diagnostics.Debug.WriteLine(ex.Message);
           throw;
       }            
   }

然后抛出异常

“An error occurred while sending the request.”

在

var response = await client.PostAsync("http://115.159.36.210/api/onehome/upload", content);

我想知道为什么并获得可以解决它的解决方案。
如果您能帮助我，我将不胜感激。

Answer 1

建议使用HttpClient和其余Windows.Web.Http名称空间API使用UWP中的HTTP 2.0和HTTP 1.1协议发送和接收信息。

根据您的要求，您可以像下面这样创建打包http POST方法的方法

public async void SendPostMethod(string url, Dictionary<string, string> param, Action<string> response)
{
    HttpClient client = new HttpClient();

    HttpResponseMessage httpResponse = new HttpResponseMessage();
    Uri requestUri = new Uri(url);

    var content = new HttpFormUrlEncodedContent(param);
    try
    {
        httpResponse = await client.PostAsync(requestUri, content);

        response(await httpResponse.Content.ReadAsStringAsync());
    }
    catch (Exception ex)
    {

    }

}

用法

 this.SendPostMethod("http://115.159.36.210/api/onehome/upload",Param, (res) =>
{

    var response = res;

});

您可以参考官方的code sample和document。

Answer 2

我是服务器的作者。

现实是我还没有完成服务器的代码。

因此，from tkinter import * from tkinter.ttk import * from tkinter.ttk import Progressbar from tkinter import ttk import tkinter as tk import tkinter.ttk, threading tkk = Tk() tkk.title("sample") tkk.geometry('350x200') number= tk.StringVar() choice= Combobox(tkk, width=12, textvariable=number) choice.grid(column=0,row=1) class progress(): def __init__(self, parent): self.progressbar = ttk.Progressbar(tkk, orient = HORIZONTAL, mode = 'indeterminate') self.t = threading.Thread() self.t.__init__(target = self.progressbar.start, args = ()) self.progressbar.grid(row=4,columnspan=6,sticky=W+E,padx=(40,10)) self.t.start() def end(self): self.progressbar.stop() self.t.join() def click(): action.configure(text="chosen case is : "+ selected.get()) print("clicked button is :") id = 0 while id < 10: progress(tkk) id+=1 else: new=progress(tkk) new.end() action = ttk.Button(tkk, text="Click", command=click) action.grid(column=1,row=1) selected= ttk.Combobox(tkk, width=12, textvariable=number) selected['values']=('a','b','c','d') selected.grid(column=0,row=1) selected.current() tkk.mainloop()是默认结果.....

我在C＃帖子中遇到系统错误

2 个答案: