我正在努力解释和理解许多位图格式选项，而我的用例是如此简单，以至于我希望有人可以向我指出正确的方向：我如何（在心理上，用笔和铅笔纸）将原始.bitmap文件转换为像素数组？我可以找到的所有其他站点都提供了一个函数或库来解决该问题，或者我无法理解各种格式设置选项之间的细微区别（以及我对.bmp和.bitmap的困惑）。
我的图像是用GIMP中的“ 13 X 11”像素网格绘制的，索引模型设置为1位，然后导出到.bitmap文件。该文件及其下面的两个ASCII表示形式被复制到下面：您应该能够在中间看到“ 73”，并且在模式的顶行和底行中也可以看到一些像素：1101001000010。
#define seventythree_with_fibbonacci_spaces_pixels_width 13
#define seventythree_with_fibbonacci_spaces_pixels_height 11
static unsigned char seventythree_with_fibbonacci_spaces_pixels_bits[] = {
0x4b, 0x08, 0x3e, 0x07, 0xa0, 0x04, 0x30, 0x04, 0x10, 0x07, 0x18, 0x04,
0x0c, 0x04, 0x84, 0x04, 0x84, 0x03, 0x00, 0x00, 0x4b, 0x08 };
/*
1101001000010
0111110011100
0000010100100
0000110000100
0000100011100
0001100000100
0011000000100
0010000100100
0010000111000
0000000000000
1101001000010
*/
/*
@@ @ @ @
@@@@@ @@@
@ @ @
@@ @
@ @@@
@@ @
@@ @
@ @ @
@ @@@
@@ @ @ @
*/
// where a 1 or @ represents a black pixel square,
// and a 0 or space is a white/blank square.
现在我的问题是：这22个 8位单词 [75，8，62，....，75，8] 和我在GIMP中绘制的原始图片？
我希望能够在GIMP中绘制简单的图像，将其转换为纯网格或位/布尔数组，然后我可以使用该数组在完全不同的上下文中重绘图片（视频游戏映射为精确，黑色像素映射到例如墙壁）。
答案 0 :(得分：0)
我相信我现在已经解决了：请看下面的python脚本（我发表了很多评论，我知道这对某些人来说是个决定性的决定！）。我正在使用python3（3.6.5）
from sys import argv # argument values
from math import ceil
"""
In GIMP, draw a WIDTH x HEIGHT Black & White picture:: Image/Mode >> Indexed...<use black and white (1 Bit) palette>:: export as .bitmap and choose the X10 format option.
This script can draw a simple ASCII image of it, or be used to get a binary
For testing, I used:
python3 convertBitMapX10_to_binary_grid.py Lev1_TD.bitmap
"""
if len(argv) > 2:
saveFileName = argv[2]
else:
saveFileName = "image_dump"
f = open(argv[1], "r")
l = [line for line in f.readlines()]
f.close()
## print(l[0])
## print(l[1])
## print(l[2])
# print(l[3])
# print(l[4])
WIDTH = int(l[0].split()[-1])
HEIGHT = int(l[1].split()[-1])
# l[3:] is our plan
l = l[3:] # lines 0 and 1 were only useful for getting the image width (x) and height (y)
# line 2 is just "static unsigned short Lev1_TD_bits[] = {"
# print([l[-1]])
# [' 0xffff, 0xffff, 0xffff, 0xffff, 0xffff, 0xffff, 0x000f };\n']
l[-1] = l[-1].strip()[:-3]
# print(l[-1])
l = [line.strip() for line in l]
# print(l[0]) #0xffff, 0xffff, 0xffff, 0xffff, 0xffff, 0xffff, 0x000f, 0xffff, 0xffff,
# print(l[-1]) #0xffff, 0xffff, 0xffff, 0xffff, 0xffff, 0xffff, 0x000f
l[-1] = l[-1] + ","
# Now every line has the same format (although l[-1] may have fewer elements)
#print(len(l[0])) #71
#print(len(l[2])) #71
#print(len(l[7])) #71
#print(len(l[-1])) #55
### NOTICE ALL OF THESE ARE === -1 IN MODULO 8 -- that's because they are missing a ' ' char at the end
# (8 == len("0xffff, "), if you wondered where '8' came from)
l = [line + " " for line in l]
l = [line.split(", ")[:-1] for line in l]
# l is now a list of lists. most of these lists have lengths of 72/8 (9), except the last, which has 7
# the elements of each of these sublists is a string like "0xffff" or "0x0000"
## the '[:-1]' clause is to cut-out the last element, which by construction will be the empty string '' and we don't want it
l = [ [ bin(int(s, 16))[2:] for s in l[i]] for i in range(len(l)) ]
# now the elements of these sublists are 16-bit strings such as "1111111111111111"
def mergelists(listOfLists):
l = []
for x in listOfLists:
l += x
return l
l = mergelists(l)
l = [i.zfill(16) for i in l]
def rev(s):
x = ""
for i in range(len(s)):
x += s[-1-i]
return x
n = ceil(WIDTH/16)
m = 16*n - WIDTH
assert len(l) == n*HEIGHT, "I believe this should always be true, else I've messed up somewhere; or maybe this isn't an X10 Format?"
def __aux_funct(l, n, i):
s = ""
for j in range(n):
s += rev(l[n*i + j])
return s
l = [ __aux_funct(l, n, i) for i in range(HEIGHT) ]
l = [line[:-m] for line in l]
##for line in l:
## print(line)
# seems to work just fine ^_^
f = open(saveFileName + ".binaryimage", "a")
BLACK_BOX = '#'
for line in l:
# print(len(line)) ## they all seem to be the same width
print("") # newline
f.write(line + "\n")
for bit in line:
print(BLACK_BOX, end='') if bit == "1" else print(" ", end='')
print("")
f.write("\n\n")
f.close()
# Beautiful <3