Question

我有以下查询：

SELECT 
    Sender, 
    DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) AS Weekdate, 
    COUNT(status) AS TranCount
FROM
    tx
WHERE 
    customer = 'ABC'
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) >= DATEADD(dd, DATEDIFF(dd, 0, GETDATE()) / 7 * 7, 0)
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) < DATEADD(dd, DATEDIFF(dd, 0, GETDATE()), 0) 
GROUP BY 
    Sender, DATEADD(dd,DATEDIFF(dd,0,Date_Reported)/7 * 7,0)

这将返回每个发件人的所有交易的列表。我想要的只有两行，包括两种发件人类型-一种是sender = "AA"，另一种是sender NOT IN "AA"。

如何将其合并到脚本中？目前，我收到了50个发件人的列表，但我只想如上所述2个发件人

预期结果

Sender            |  Weekdate      |  TranCount
AA                |    25/06/2018  |      33
"Not Sender AA"   |    25/06/2018  |      26

Answer 1

使用简单的CASE语句：

SELECT 
    CASE Sender WHEN 'AA' THEN Sender ELSE 'Not Sender AA' END AS Sender, 
    DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) AS Weekdate, 
    COUNT(status) AS TranCount
FROM
    tx
WHERE 
    customer = 'ABC'
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) >= DATEADD(dd, DATEDIFF(dd, 0, GETDATE()) / 7 * 7, 0)
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) < DATEADD(dd, DATEDIFF(dd, 0, GETDATE()), 0) 
GROUP BY 
    CASE Sender WHEN 'AA' THEN Sender ELSE 'Not Sender AA' END, DATEADD(dd,DATEDIFF(dd,0,Date_Reported)/7 * 7,0)

请注意，您必须在GROUP BY子句中放入相同的CASE语句。

Answer 2

工会呢？诸如此类（很抱歉，那里没有MS SQL Studio）

SELECT 
    Sender, 
    DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) AS Weekdate, 
    COUNT(status) AS TranCount
FROM
    tx
WHERE 
    sender = 'AA' and 
   customer = 'ABC'
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) >= DATEADD(dd, DATEDIFF(dd, 0, GETDATE()) / 7 * 7, 0)
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) < DATEADD(dd, DATEDIFF(dd, 0, GETDATE()), 0) 
GROUP BY 
    Sender, DATEADD(dd,DATEDIFF(dd,0,Date_Reported)/7 * 7,0)
union 
SELECT 
    'Not Sender AA', 
    DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) AS Weekdate, 
    COUNT(status) AS TranCount
FROM
    tx
WHERE 
    Sender <> 'AA' and
    customer = 'ABC'
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) >= DATEADD(dd, DATEDIFF(dd, 0, GETDATE()) / 7 * 7, 0)
    AND DATEADD(dd, DATEDIFF(dd, 0, Date_Reported) / 7 * 7, 0) < DATEADD(dd, DATEDIFF(dd, 0, GETDATE()), 0) 
GROUP BY 
    DATEADD(dd,DATEDIFF(dd,0,Date_Reported)/7 * 7,0)

SQL将多行分组为2行

2 个答案: