Question

我有一个如下的数据集 http://sqlfiddle.com/#!18/149382/2

结果应该如下

TripGroup  Grouper1      Grouper2      Date         Hour              Code    Description
1          6EA579BEA901  58639247D5CB  2018-02-03   00:01:00.0000000  3962X1  GARAG EXTRA
1          6EA579BEA901  58639247D5CB  2018-02-03   00:03:00.0000000  3962X2  RET  EXTRA/GARAG
2          6EA579BEA901  58639247D5CB  2018-02-03   05:45:00.0000000  3962X1  GARAG EXTRA
2          6EA579BEA901  58639247D5CB  2018-02-03   07:30:00.0000000  3962X2  RET  EXTRA/GARAG
3          6EA579BEA901  58639247D5CB  2018-02-03   05:55:00.0000000  3962X1  GARAG EXTRA
3          6EA579BEA901  58639247D5CB  2018-02-03   07:30:00.0000000  3962X2  RET  EXTRA/GARAG
4          6EA579BEA901  58639247D5CB  2018-02-03   14:45:00.0000000  3962X1  GARAG EXTRA
4          6EA579BEA901  58639247D5CB  2018-02-03   15:40:00.0000000  3962X2  RET  EXTRA/GARAG

我的问题是在RET

之前2 GARAG启动

所有组都应该有一行以GARAG开头，一行以RET

开头

Answer 1

我猜这是你想要的。您还可以将where子句中的Description更改为Code。但如果没有，请告诉我并寻找答案。希望这可以帮助。感谢。

 SELECT row_number() over (partition by Grouper1, Grouper2 order by Date, Hour) as TripGroup,
  Grouper1,
  Grouper2,
  Date,
  Hour,
  Code,
  Description
FROM FOO
where Description = 'GARAG EXTRA'
UNION ALL
SELECT row_number() over (partition by Grouper1, Grouper2 order by Date, Hour) as TripGroup,
  Grouper1,
  Grouper2,
  Date,
  Hour,
  Code,
  Description
FROM FOO
where Description = 'RET  EXTRA/GARAG'
order by TripGroup, Description;

Result:
TripGroup  Grouper1      Grouper2      Date         Hour              Code    Description
1          6EA579BEA901  58639247D5CB  2018-02-03   00:01:00.0000000  3962X1  GARAG EXTRA
1          6EA579BEA901  58639247D5CB  2018-02-03   00:03:00.0000000  3962X2  RET  EXTRA/GARAG
2          6EA579BEA901  58639247D5CB  2018-02-03   05:45:00.0000000  3962X1  GARAG EXTRA
2          6EA579BEA901  58639247D5CB  2018-02-03   07:30:00.0000000  3962X2  RET  EXTRA/GARAG
3          6EA579BEA901  58639247D5CB  2018-02-03   05:55:00.0000000  3962X1  GARAG EXTRA
3          6EA579BEA901  58639247D5CB  2018-02-03   07:30:00.0000000  3962X2  RET  EXTRA/GARAG
4          6EA579BEA901  58639247D5CB  2018-02-03   14:45:00.0000000  3962X1  GARAG EXTRA
4          6EA579BEA901  58639247D5CB  2018-02-03   15:40:00.0000000  3962X2  RET  EXTRA/GARAG

Answer 2

如果你想要一行以GARAG开头，一行以RET开头，那么这个怎么样？

schema

每组最多2行的行组

2 个答案: