Question

我有一个简单的问题。

我有多种方法可以从我无法控制的其他应用程序获取JSON。所有键都具有相同的名称，但是有些键是大写的，有些是小写的。

我如何读取JSON，所以不管是小写还是大写？

例如在我的代码中，当json的customer_id小写时不起作用

我当前的功能不起作用。我需要一个通用函数，该函数将长度为1或更多的json对象的键转换为大写

HTML

 <td ng-repeat="customer in customers">{{customer.CUSTOMER_ID}}</td> // this only works when the JSON keys comes uppercase

控制器

 //another function
 $http.get(baseUrl + param).then(function (response) {
        console.log(response.data.items);
        console.log(normalizeJSON(response.data.items));
        $scope.customers = normalizeJSON(response.data.items);
    });
};

function normalizeJSON (jsonObject) {
    var parsedObjectWithLowerCaseKeys = {};

    for(var i = 0; i < jsonObject.length; i++) {
        Object.keys(jsonObject[i]).forEach(function (itemKey) {
            parsedObjectWithLowerCaseKeys[itemKey.toUpperCase()] = jsonObject[itemKey];
        });

        return parsedObjectWithLowerCaseKeys;
    }
}

response.data.items给出

[
  {
    "account_id": 4,
    "account_type_description": "Joint Account",
    "customer_id": 4,
    "first_name": "Clark",
    "last_name": "Kent",
    "identity_card_number": 2132142134,
    "tax_identification": 2892031234,
    "birth_date": "2018-06-28T07:57:23Z",
    "customer_gender_description": "Male",
    "street_address": "Gotham Street 56",
    "postal_code": "21312",
    "city": "Gotham",
    "country_description": "Portugal"
  },
  {
    "account_id": 4,
    "account_type_description": "Joint Account",
    "customer_id": 5,
    "first_name": "Cristiano",
    "last_name": "Ronaldo",
    "identity_card_number": 2132142135,
    "tax_identification": 2892031235,
    "birth_date": "2018-06-28T07:57:23Z",
    "customer_gender_description": "Male",
    "street_address": "Gotham Street 56",
    "postal_code": "21312",
    "city": "Gotham",
    "country_description": "Portugal"
  }
]

编辑：不同

Answer 1

如下更新功能。

function normalizeJSON (jsonObject) {
    var newJsonObject = [];

    for(var i = 0; i < jsonObject.length; i++) {
        var parsedObjectWithLowerCaseKeys = {};
        Object.keys(jsonObject[i]).forEach(function (itemKey) {
            parsedObjectWithLowerCaseKeys[itemKey.toUpperCase()] = jsonObject[i][itemKey];
        });
        newJsonObject.push(parsedObjectWithLowerCaseKeys);
    }
    return newJsonObject;
}

将键转换为大写

1 个答案: