Question

$name1 = @$_GET['search'] ;
$name = split(" +",$name1);
$query = "select * from table where field1 = '".$name[0]."'
and field2 = '".$name[1]."'
Order By `date` DESC";

我进行了类似的简单搜索，但如果$name[0]和$name[1]都有数据，则查询可以正常工作，如果$name[1]为空，则查询失败。如何添加判断如果$name[1]为空，隐藏and field2 = '".$name[1]."'，并进行类似

的查询

$query = "select * from table where field1 = '".$name[0]."' Order By日期DESC";

Answer 1

您可以使用or：

执行此操作

(and field2 = '".$name[1]."' or '".$name[1]."' = '')

Answer 2

试试这个

 if(!empty($name[0]) or !empty($name[1])){
    $sql = "select * from table where ";

    if($name[0]){
       $fld1 = " field1 = '".$name[0]."'";           
    }
    if($name[1]){
       $fld2 = " field2 = '".$name[1]."'";           
    }

    if($fld1 && $fld2)
    {
        $sql .= $fld1 ." and ".$fld2;
    }
    elseif($fld1){
        $sql .= $fld1;
    }
    elseif($fld2){
        $sql .= $fld2;
    }

 }

Answer 3

如果你在PHP脚本中，这样做会更好


$query = "select * from table where field1 = '$name[0]'"
if ($name[1]) $query .= " and field2 = '$name[1]'";
$query .= 'order by date desc';

Answer 4

$name[1]?'query of it exists':'query if it doesn't';

php选择从哪里和问题

4 个答案: