Question

我想得到我桌子上一个单元格的内容。我的代码是这个 - ＆gt;

session_start();
$username = $_SESSION["username"];
// Connect to your Database 
mysql_connect("localhost", "root", "*!#@%#") or die(mysql_error()); 

//Select DB
mysql_select_db("yplay") or die(mysql_error()); 

$PlayList = mysql_query("SELECT * FROM users WHERE username=" . $username);
$videos = $PlayList["playlist"];

该单元格的内容必须在$ videos

中

由于

Answer 1

session_start();

$username = $_SESSION["username"];

mysql_connect("localhost", "root", "*!#@%#") or die(mysql_error()); 

mysql_select_db("yplay") or die(mysql_error()); 

$PlayListQuery = mysql_query("SELECT * FROM users WHERE username=" . $username." LIMIT 1");

$PlayList = mysql_fetch_assoc($PlayListQuery); // Do something with the result set from the query

$videos = $PlayList["playlist"];

Answer 2

试试这个

session_start();
$username = $_SESSION["username"];
// Connect to your Database 

$hostname = "localhost";
$username = "root";
$password = "*!#@%#";
$db_name = "yplay";

$conn = mysql_connect("localhost", "root", "*!#@%#") or die(mysql_error()); 

//Select DB
mysql_select_db($db_name, $conn) or die(mysql_error()); 


$username = mysql_real_escape_string(stripslahes($username));    // to prevent mysql injections             
$result = mysql_query("SELECT * FROM users WHERE username='$username' LIMIT 1 ") or die(mysql_error());
if($row = mysql_fetch_assoc($res))
{
    $videos = $row["playlist"];
}
else
{
    echo "No username exists in the table";
}

MYSQL从AND Where中选择

2 个答案: