PHP MySQL联接两个表查询

时间:2018-06-23 17:38:13

标签: php mysql pdo

我有两个表,即抽象表和具有一对多关系的作者,对于while循环上的每次迭代,我想显示抽象表中唯一数据行的html表,以及作者表中的相应行。

这就是我所做的:

public function getAll() {
    try {
          $sql = "  SELECT tbl_abstract.abstract_id, tbl_abstract.first_name,
                            tbl_abstract.last_name,tbl_abstract.content,        
                            tbl_author.afirst_name, tbl_author.alast_name, 
                            tbl_author.aaffilition 
                    FROM tbl_abstract  
                        INNER JOIN tbl_author ON  tbl_abstract.abstract_id = tbl_author.abstract_id 
                    GROUP BY tbl_abstract.abstract_id";

          $stmt= $this->pdo->prepare($sql);
          $stmt->execute();
          $count =  $stmt ->rowCount();
          while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
          ?>

             <table class="table" >
              <tr>
                <td  align="center" >
                   //data from tbl_abstract
                   <?php echo $row["abstract_id"];  ?>. <?php print($row["abstract_title"]); ?>
                    <?php echo $row["first_name"].'&nbsp;'.$row["last_name"]; ?>,

                    //data from tbl_author
                    <?php echo $row["afirst_name"].'&nbsp;'.$row["alast_name"];?>         
                </td>  
              </tr>
              <tr>
                <td align="center" ">
                   //data from tbl_abstract
                   <?php print($row["content"]); ?>
                </td>
              </tr>

            </table>
          <?php 
         }          
    }catch(PDOException $e){
       echo $e->getMessage(); 
       return false;
    }  
}

tbl_author中有3条记录与tbl_abstract中的abstract_id相关联,但我只得到一条记录,而不是3条。请帮助

2 个答案:

答案 0 :(得分:0)

尝试像这样删除GROUP BY子句:

SELECT 
    tbl_abstract.abstract_id, tbl_abstract.first_name, 
    tbl_abstract.last_name,tbl_abstract.content, tbl_author.afirst_name, 
    tbl_author.alast_name, tbl_author.aaffilition 
FROM 
    tbl_abstract  
INNER JOIN 
    tbl_author ON  tbl_abstract.abstract_id = tbl_author.abstract_id

Group by会将所有作者按abstract_id字段分组,这意味着它不会返回所有作者,而是仅返回一个作者的一个abstract_id(基于排序字段,在这种情况下可能是主键) ,因为未明确定义)。

答案 1 :(得分:0)

试试这个:-

<?php

$sql = "SELECT * 
        FROM tbl_abstract
        where abstract_id IN (SELECT distinct abstract_id
                              FROM tbl_abstract)";

      $stmt= $this->pdo->prepare($sql);
      $stmt->execute();
      $count =  $stmt ->rowCount();
?>
      <table class="table" >
      while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
      ?>
          <tr>
            <td  align="center" >
               //data from tbl_abstract
               <?php echo $row["abstract_id"];  ?> <?php print($row["abstract_title"]); ?>
                <?php echo $row["first_name"].'&nbsp;'.$row["last_name"]; ?>,
         <?php          
         $sql1 = "SELECT *
                  FROM tbl_author
                  WHERE abstract_id = '".$row["abstract_id"]."'" ;
         $stmt1= $this->pdo->prepare($sql1);
         $stmt1->execute();
         while($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)){
                //data from tbl_author
                echo $row1["afirst_name"].'&nbsp;'.$row1["alast_name"];
         } ?>         
            </td>
            <td align="center">
               //data from tbl_abstract
               <?php print($row["content"]); ?>
            </td>
          </tr>
       <?php } ?>

        </table>