我是MYSQL的新手。任何有关这方面的帮助将不胜感激。
我有两张表机场和帖子,包含以下字段:
机场
id, Airport-code, Airport_name
帖子
id, Source_Airport_code, Destination_airport_code, Date_of_departure, preference
如何获取包含以下字段的记录(此处Source和Destination对应于机场名称而不是代码):
Source, destination, date_of_departure
答案 0 :(得分:2)
如果Posts.*_Airport_code
中的FK未引用Airports.id
为MJB假定,而是Airports.Airport_code
,那么
SELECT
APS.Airport_name AS Source,
APD.Airport_name AS Destination,
Posts.date_of_departure
FROM Posts
INNER JOIN Airports APS ON(APS.Airport_code = Posts.Source_Airport_code)
INNER JOIN Airports APD ON(APD.Airport_code = Posts.Destination_airport_code)
答案 1 :(得分:0)
尝试此操作:
select
s.airport_name as source,
d.airport_name as destination,
p.date_of_departure
from posts p
inner join airports s
on p.source_airport_code = s.id
inner join airports d
on d.source_airport_code = d.id
我不想这么说,但我认为你还有很长的路要走。