我有一个文本文件,如下所示:
1 1 2 1 1e8
2 1 2 3 1e5
3 2 3 2 2000
4 2 5 6 1000
5 2 4 3 1e4
6 3 6 4 5000
7 3 5 2 2000
8 3 2 3 5000
9 3 4 5 1e9
10 3 2 3 1e6
我的问题是,如何更改一列(例如将所有数据从最后一列除以900)并将整个数据保存在一个新文件中? 预先感谢
答案 0 :(得分:0)
对于文件的每一行,
vals = line.split(' ')
my_val = float(vals[4])/900
output = open('filename', 'wb')
output.write(my_val +'\n')
答案 1 :(得分:0)
您可以使用numpy库。下面的代码可以做到这一点。
import numpy as np
# assume the data is in.txt file
dat = np.loadtxt('in.txt')
# -1 means the last column
dat[:, -1] = dat[:, -1]/900
# write the result to the out.txt file
# fmt is the format while writing to the file
# %.2f means that it will save it to the 2 digits precision
np.savetxt('out.txt', dat, fmt='%.2f')
答案 2 :(得分:0)
使用简单的迭代。
res = []
with open(filename, "r") as infile:
for line in infile: # Iterate each line
val = line.split() # Split line by space
res.append( str(float(val[-1])/900) ) # Use negative index to get last element and divide.
with open(filename, "w") as outfile: #Open file to write
for line in res:
outfile.write(line+"\n") #Write Data
答案 3 :(得分:0)
您可以尝试以下操作:
import numpy as np
#Suppose your text data name is "CH3CH2OH_g.txt"
file = np.loadtxt('CH3CH2OH_g.txt')
z= (file[:, -1]/900)
np.savetxt('LogCH3CH2OH.txt', file, fmt='%.2f')