Question

我希望调整现有代码，以解决两个datetime值之间经过的分钟和秒的问题。我目前正在抽出过去的时间，但最好是采用HH：MM：SS格式，而不是仅仅几个小时，但是我似乎找不到任何能解决我问题的文档。

Select 
    convert(datetime, Left(Replace(Create_Date, 'T', ' '), 19)) as CreateDate2,
    case 
       when Resolution_date = 'None' then '1999-01-01 12:00:00'
       when Resolution_date <> 'None' then convert(datetime, left(replace(resolution_date, 'T', ' '), 19))
    end as ResolutionDate2,
    datediff(hour, convert(datetime, left(replace(Create_Date, 'T', ' '), 19)), 
    case 
       when Resolution_date = 'None' then '1999-01-01 12:00:00'
       when Resolution_date <> 'None' then convert(datetime, left(replace(Resolution_date, 'T', ' '), 19)) 
    end) as HoursPassed,
    *
from 
    xyz 
where 
    abc;

更具体地说，此部分来自上面的代码：

datediff(hour, convert(datetime,Left(Replace(Create_Date, 'T', ' '), 19)), 
case 
    when Resolution_date = 'None' then '1999-01-01 12:00:00'
    when Resolution_date <> 'None' then convert(datetime, left(replace(Resolution_date, 'T', ' '), 19)) 
end) as HoursPassed

datetime列最初采用以下格式：

2017-05-25T15:58:26.000+0000

当前结果如下：

2017-05-23 19:51:59.000  2017-05-24 12:38:17.000        17
2017-05-24 15:10:50.000  2017-05-24 16:31:23.000         1
2017-05-25 15:58:26.000  2017-05-25 16:03:30.000         1

Answer 1

您可以将秒数转换为时间。我不容易遵循您代码的逻辑，但是转换非常简单：

select cast(dateadd(second,
                    datediff(second, <starttime>, <enddatime>),
                    0) as time
           )

SQL-datediff返回小时，但我想在HH：MM：SS中添加分钟和秒

1 个答案: