Question

我需要使用Sql Server 2008

来计算小时，分钟和秒

字段仅包含时间值。

输入

ID       HORA_S  
--  ----------------------
1   1899-12-30 18:22:50.000
2   1899-12-30 18:22:50.000
3   1899-12-30 18:30:50.000

输出

HOURS  MINUTES SECONDS
----   ---     --------
55     16      30

在玩了这段代码后，我解决了!!!

SELECT  SUM(DATEPART(hh, CAST(HORA_S AS DATETIME))) 
        + ( SUM(DATEPART(MINUTE, CAST(HORA_S AS DATETIME))) / 60 )
        + ( SUM(DATEPART(MINUTE, CAST(HORA_S AS DATETIME))) % 60
        + ( SUM(DATEPART(SECOND, CAST(HORA_S AS DATETIME))) / 60 ) ) / 60 AS HORAS,
    ( SUM(DATEPART(MINUTE, CAST(HORA_S AS DATETIME))) % 60
        + ( SUM(DATEPART(SECOND, CAST(HORA_S AS DATETIME))) / 60 ) ) % 60 AS MINUTOS,
    SUM(DATEPART(SECOND, CAST(HORA_S AS DATETIME))) % 60 AS SEGUNDOS FROM Table

Answer 1

这是一个带有少量代码的工作示例

样本表

DECLARE @T TABLE (ID int, HORA_S datetime)
insert @T values
(1, '1899-12-30 18:22:50.000'),
(2, '1899-12-30 18:22:50.000'),
(3, '1899-12-30 18:30:50.000')

;WITH T(V) AS (
    SELECT convert(datetime,SUM(convert(float, 2+hora_s)))
    FROM @T
)
SELECT
    [HOURS]   = floor(convert(float,V)*24),
    [MINUTES] = DATEPART(MI,V),
    [SECONDS] = DATEPART(SS,V)
FROM T

注意：查询中的2+假定按storing time only，日期部分始终为1899-12-30。我知道Delphi将该日期用作0天。

如何计算小时，分钟和秒？

1 个答案: