Question

我有带100个日期的testDates.csv

date
1/10/17
6/10/18
9/10/42
...

我制作了一个脚本，可以根据以下日期创建示例密码：

Model

我想将创建的密码导出到新列中的原始.csv。因此，在“日期”旁边有一列“密码”，以查看我的脚本是否正常运行。示例：

date    password
1/10/17 Winter17
6/10/18 Summer18
9/10/42 Fall42
...     ...

我知道它涉及$file = Import-Csv -Path U:\Desktop\testDates.csv foreach ($line in $file) { $fullDate = $line.date $year = Get-Date $fullDate -Format "yy" $currentDate = Get-Date $fullDate -Format "MM-dd" # Determining season if ($currentDate -ge (Get-Date 01-01) -and $currentDate -lt (Get-Date 03-01)) { $season = "Winter" } elseif ($currentDate -ge (Get-Date 03-01) -and $currentDate -le (Get-Date 05-31)) { $season = "Spring" } elseif ($currentDate -ge (Get-Date 06-01) -and $currentDate -le (Get-Date 08-31)) { $season = "Summer" } elseif ($currentDate -ge (Get-Date 09-01) -and $currentDate -le (Get-Date 11-30)) { $season = "Fall" } elseif ($currentDate -ge (Get-Date 12-01) -and $currentDate -le (Get-Date 12-31)) { $season = "Winter" } else { $season = "ClearyAnIntern" } # Creating password $SamplePassword = $season + $year }，但是我不知道如何特别是在每行中使用它。我一直在查看大量不同的线程，并在MS帮助中心中找到了如何使用诸如Export-Csv之类的不同参数的方法，但是我所看到和尝试的一切都不完全是我要处理的内容。并且从这些示例中推断目前不在我的补救知识范围内。我开始相信这可能涉及嵌套的-Append循环。

Answer 1

Export-Csv需要一个对象列表作为输入，因此这是您首先需要创建的。

foreach ($line in $file) {
    ...
    [PSCustomObject]@{
        'date'     = $fullDate
        'password' = $SamplePassword
    }
}

接下来，foreach循环无法写入管道，因此您要么需要在循环内附加到输出文件：

foreach ($line in $file) {
    ...
    [PSCustomObject]@{
        'date'     = $fullDate
        'password' = $SamplePassword
    } | Export-Csv 'output.csv' -NoType -Append
}

或将输出收集到变量中，然后将其导出：

$list = foreach ($line in $file) {
    ...
    [PSCustomObject]@{
        'date'     = $fullDate
        'password' = $SamplePassword
    }
}

$list | Export-Csv 'output.csv' -NoType

否则，您需要将foreach循环替换为ForEach-Object循环：

Import-Csv 'U:\Desktop\testDates.csv' | ForEach-Object {
    $fullDate = $_.date
    ...
    [PSCustomObject]@{
        'date'     = $fullDate
        'password' = $SamplePassword
    }
} | Export-Csv 'output.csv' -NoType

Answer 2

您可以将Calculated properties与for循环结合使用。如下图所示-

#Importing csv dates file
$file = Import-Csv -Path U:\Desktop\testDates.csv

#Declaring the variable to store passwords
$SamplePassword = @()

#loop
foreach ($line in $file)
{
    #Variable declarations
    $fullDate = $line.date
    $year = get-date $fullDate -Format "yy"
    $currentDate = get-date $fullDate -Format "MM-dd"

    #Determining season
    if ($currentDate -ge (get-date 01-01) -and $currentDate -lt (get-date 03-01))
        {$season = "Winter"}
    elseif ($currentDate -ge (get-date 03-01) -and $currentDate -le (get-date 05-31))
        {$season = "Spring"}
    elseif ($currentDate -ge (get-date 06-01) -and $currentDate -le (get-date 08-31))
        {$season = "Summer"}
    elseif ($currentDate -ge (get-date 09-01) -and $currentDate -le (get-date 11-30))
        {$season = "Fall"}
    elseif ($currentDate -ge (get-date 12-01) -and $currentDate -le (get-date 12-31))
        {$season = "Winter"}
    else{
    $season = "ClearyAnIntern"
    }

    #Creating password
    $SamplePassword += $season + $year
}

完成上述步骤后，您的$SamplePassword将包含所有密码。将计算的属性与for循环一起使用，如下所示-

#Declaring a new variable to store the results
$NewCsv = @()
$Originalcsv = Import-Csv -path U:\Desktop\testDates.csv
for($i = 0; $i -lt $Originalcsv.Length; $i++)
{
    $NewCsv += $Originalcsv[$i] | Select-Object *, @{Name='Password';Expression={$SamplePassword[$i]}}
}

$NewCsv | Export-Csv U:\Desktop\NewtestDatesWithPasswords.csv -NoTypeInformation

Answer 3

我只猜您的csv文件中的日期的格式为M/d/yy？从csv导入时，变量类型始终是字符串，因为我自己的语言环境有所不同，因此我必须定义不同的区域性进行转换。

使用我的function Get-Season的其他问题的修改版本。

## Q:\Test\2018\06\21\SO_50976425.ps1
## define function first
Function Get-Season([datetime]$Date){
    If (!$Date) {$Date = Get-Date} #If date was not provided, assume today.
    # The dates are obviously not exactly accurate and are best guesses
    $Spring = Get-Date -Day 20 -Month 03 -Year $Date.Year
    $Summer = Get-Date -Day 21 -Month 06 -Year $Date.Year
    $Autumn = Get-Date -Day 22 -Month 09 -Year $Date.Year
    $Winter = Get-Date -Day 21 -Month 12 -Year $Date.Year
    $Season = switch($Date) {
        {($_ -lt $Spring)}  {"Winter";Break}
        {($_ -lt $Summer)}  {"Spring";Break}
        {($_ -lt $Autumn)}  {"Summer";Break}
        {($_ -lt $Winter)}  {"Autumn";Break}
        {($_ -ge $Winter)}  {"Winter"}
    }
    "{0}{1}" -f $Season,$Date.ToString('yy')
}

#Importing csv dates file
$file = Import-Csv -Path '.\testDates.csv'

# get CultureInfo
$CIUS = New-Object System.Globalization.CultureInfo("en-US")

# process $file and create a new PSCustomObject
$DatePassw = foreach ($line in $file){
    $fullDate = [datetime]::ParseExact($line.date,"M/d/yy",$CIUS)
    [PsCustomObject]@{
        date     = $line.date
        password = (Get-Season $fulldate)
    }
}
$DatePassw | ft
$DatePassw | Export-Csv '.\testdatepassw.csv' -NoTypeInformation

示例输出：

> .\SO_50976425.ps1

date    password
----    --------
1/10/17 Winter17
6/10/18 Spring18
9/10/42 Summer42

> gc .\testdatepassw.csv
"date","password"
"1/10/17","Winter17"
"6/10/18","Spring18"
"9/10/42","Summer42"

Answer 4

Import-Csv C:\path\input.csv | ForEach-Object {
   $seasons = [Char[]]'wwsssmmmfffw' # seasons map
}{ # walk around CSV lines
   [PSCustomObject]@{
      Date = $_.date # first and second columns of future CSV
      Password = "$(switch ($seasons[([DateTime]$_.date).Month - 1]) {
         'w' {'Winter'} 's' {'Spring'} 'm' {'Summer'} 'f' {'Fall'}
      })$(Get-Date $_.date -Format yy)"
   }
} | Export-Csv C:\path\out.csv # export result

导入/导出.csv文件

4 个答案: