我正在尝试使用fitdist
包中的fitdistrplus
函数来使数据适合Burr分布。
library(fitdistrplus)
library(actuar)
fit_bur <- fitdist(data=c(6,8,6,3,3,6,6,6,7,8,4,5,1,4,4,0,0,0,0,7,5,6,6,5,3,4,8,6,5,6,3,6,5,4,3,9,4,2,4), method = "mle",distr="burr",
start = list(shape1 = 0.3, shape2 = 1, rate = 1))
受here发布的问题的启发,我注意到错误可能是我的数据包含0个值,因此我将0.1加到所有0个值上。
fit_bur <- fitdist(data=c(6,8,6,3,3,6,6,6,7,8,4,5,1,4,4,0.1,0.1,0.1,0.1,7,5,6,6,5,3,4,8,6,5,6,3,6,5,4,3,9,4,2,4), method = "mle",distr="burr",
start = list(shape1 = 0.3, shape2 = 1, rate = 1))
这个问题有解决方案吗?感谢您的帮助。
答案 0 :(得分:1)
尝试此代码,即使它会给您带来标准错误的机会:
data_you <- c(6,8,6,3,3,6,6,6,7,8,4,5,1,4,4,0.1,0.1,0.1,0.1,7,5,6,6,5,3,4,8,6,5,6,3,6,5,4,3,9,4,2,4)
fit_bur <- fitdist(data_you,"burr", start = list(shape1 = 0.3, shape2 = 1, rate = 1),lower=c(0,0))